3. The following data represent the age (in weeks) at which babies first crawl based on asurvey of 14 mothers.52, 30, 44, 35, 39, 26, 47, 37, 56, 26, 39, 28, 38, 34(You can assume that the data come from a normally distributed population and that thereare no outliers.)Construct and interpret a 90% confidence interval for the mean age at which a baby firstcrawls.

Answered: Image /qna-images/answer/15704e9a-6089-49cc-8311-fd4c32801d89.jpg

Answered: 3. The following data represent the age…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A survey of 97 random homeowners in my neighborhood had a mean of $720 spent on lawn care. Construct a 98% confidence interval for the mean lawn care expenditure per household when the population variance is $400.
A second-semester junior at a large high school wants to estimate the number of colleges a senior applies to on average before deciding where they will attend. The junior randomly selects 19 seniors and asks them how many colleges they applied to and records the number. Use the data below to construct a 99% confidence interval to estimate the true mean number of colleges seniors at this school apply to before deciding about which college to attend. 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 7, 7, 8, 9 3. Do. Use technology to find the mean and standard deviation of the sample. Round each answer to 2 decimal places. Use those values and t* from the table to calculate the confidence interval. Round the endpoints to 1 decimal place. 99% confidence interval is (, )
(in hours): 7, 6, 7, 8.5, 8, 9, 6.5 a. Find the mean, median, mode and standard deviation for their hours of sleep. b. Create a 99% confidence interval for the mean amount of hours they slept.
4. At private college the achievement test is used for advanced study placement. Counselors selected a random sample of 144 students from the college and scored their tests by hand before sending them in for computer processing. For this sample, the mean was 450 and s = 29. Construct a 98% confidence interval for the mean.
Help!!
An apartment hunter is shopping for either a one-bedroom or two-bedroom apartment in varying apartment buildings. She wants to estimate the additional amount she would have to pay, on average, for a two-bedroom apartment versus a one-bedroom apartment. The table shows the prices, in dollars, for one- and two-bedroom apartments from the nine buildings she visited. A 95% confidence interval for the true mean difference between two-bedroom and one-bedroom apartments for apartment buildings like the ones in the sample was (255.93, 508.51). A friend of the apartment hunter tells her to expect to pay about $500 more per month for a two-bedroom apartment than for a one-bedroom apartment. Does the confidence interval provide evidence for the friend’s claim? A. No, the confidence interval does not contain 0, so the friend’s claim is not plausible. B. No, the confidence interval contains many more numbers below 500 than above 500, so it is unlikely that the friend’s assertion is correct. C.…
Fuel efficiency of Prius: Fueleconomy.gov, the official US government source for fuel economy information, allows users to share gas mileage information on their vehicles. The histogram below shows the distribution of gas mileage in miles per gallon (MPG) from 14 users who drive a 2012 Toyota Prius. The sample mean is 53.3 MPG and the standard deviation is 5.2 MPG. Note that these data are user estimates and since the source data cannot be verified, the accuracy of these estimates are not guaranteed. (a) The EPA claims that a 2012 Prius gets 50 MPG (city and highway mileage combined). Do these data provide strong evidence against this estimate for drivers who participate on fueleconomy.gov? The test statistic is: __________________(please round to two decimal places)The p-value:___________________________ for this hypothesis test is: (please round to four decimal places)(c) Please comment on the primary thing that is wrong about the following statement: There is sufficient evidence…
Car and Driver Magazine tested a random sample of 9 hybrid cars and found their MPG to be 42, 51, 39, 44, 52, 48, 51, 44, and 47. Construct a 95% confidence interval for the population variance.
do the last one please
10. Several years ago, 51% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,075 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,075 surveyed, 472 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed. What are the null and alternative hypotheses? Ho: p (1) versus H1: p (2) (Round to two decimal places as needed.) Use technology to find the 99% confidence interval. The lower bound is The upper bound is (Round to two decimal places as needed.) What is the correct conclusion? O A. Since the interval contains the proportion stated in the null hypothesis, there is insufficient evidence that parents' att O B. Since the interval contains the proportion stated in the null hypothesis, there is sufficient…

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