**Hypothesis Testing Problem**11. In a survey, 31% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too high, so he randomly selected 170 pet owners and discovered that 47 of them spoke to their pet on the telephone. Does the veterinarian have a right to be skeptical? Use the α = 0.1 level of significance.**Standard Normal Distribution Tables:**- [View standard normal distribution table (page 1)](link)- [View standard normal distribution table (page 2)](link)**Conditions to Validate:***Because* $ n p_0 (1 - p_0) = \underline{\hspace{2cm}} (1) $ *is at least* 10, *the sample size is* $ \underline{\hspace{1cm}} (2) $ *5% of the population size, and the sample* $ \underline{\hspace{1cm}} (3) $ *the requirements for testing the hypothesis* $ \underline{\hspace{1cm}} (4) $ *are satisfied.**Round to one decimal place as needed.***Hypotheses:**- Null hypothesis ($ H_0 $): $ \underline{\hspace{1cm}} (5) $ $ \underline{\hspace{1cm}} (6) $ $ \underline{\hspace{1cm}} $ *versus* - Alternative hypothesis ($ H_1 $): $ \underline{\hspace{1cm}} (7) $ $ \underline{\hspace{1cm}} (8) $*Type integers or decimals. Do not round.***Test Statistic** ($ z_0 $):- $ z_0 = \underline{\hspace{2cm}} $ *(Round to two decimal places as needed.)***Critical Values:**Select the correct choice below and fill in the answer box to complete your choice.*(Round to two decimal places as needed.)*- A. $ \pm z_{\alpha / 2} = \pm \underline{\hspace{1cm}} $- B. $ z_{\alpha} = \underline{\hspace{1cm}} $**Conclusion:**Does the veterinarian have a right to be skeptical?Choose one:- A. The veterinarian 10. Several years ago, 51% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,075 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,075 surveyed, 472 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed.What are the null and alternative hypotheses?H₀: p (1) ____________ versus H₁: p (2) ____________(Round to two decimal places as needed.)Use technology to find the 99% confidence interval.The lower bound is ____________.The upper bound is ____________.(Round to two decimal places as needed.)What is the correct conclusion?- A. Since the interval contains the proportion stated in the null hypothesis, there is insufficient evidence that parents' attitudes have changed.- B. Since the interval contains the proportion stated in the null hypothesis, there is sufficient evidence that parents' attitudes have changed.- C. Since the interval does not contain the proportion stated in the null hypothesis, there is sufficient evidence that parents' attitudes have changed.- D. Since the interval does not contain the proportion stated in the null hypothesis, there is insufficient evidence that parents' attitudes have changed.(1) ⃝ > (2) ⃝ > (1) ⃝ < (2) ⃝ = (1) ⃝ ≠ (2) ⃝ < (1) ⃝ = (2) ⃝ ≠

As per the honor code, We’ll answer the first question since the exact one wasn’t specified. Please submit a new question by specifying the one you’d like answered in the remaining questions That is Q. 10 's answer is providing. Given, p = 0.51 N = 1075 X = 472 Confidence level = 99% = 0.99 To find, What are the null and alternative hypothesis? 99% confidence interval? What is the correct conclusion?What are the null and alternative hypothesis? Answer: This is the Two tailed test. The null and alternative hypothesis is: H0: p = 0.51 Vs Ha: p ≠ 0.5199% confidence interval? Answer: We need to construct the 99% confidence interval for the population proportion. We have been provided with the following information about the number of favorable cases: Favorable cases = X = 472 Sample size = N = 1075 The sample proportion is computed as follows, p^ = XN = 4721075 = 0.4391 The critical value for α=0.01 is Zc = Z1−α/2 = 2.576. The corresponding confidence interval is computed as shown below: CI = p^ ± Zc × p^ (1 - p^)nCI = 0.4391 ± 2.576 × 0.4391 (1 - 0.4391)1075CI = 0.4391 ± 0.039Lower bound = 0.4391 - 0.039 = 0.4001Upper bound = 0.4391 + 0.039 = 0.4781 The Lower bound is = 0.40 The upper bound is = 0.48What is the correct conclusion? Answer: The correct option is: C) Since, the interval does not contain the proportion stated in the null hypothesis, there is sufficient evidence that parents attitudes towards the quality of education have changed.