A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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  1. Make a Stem-Leaf Plot 2. Box-Whisker Plot 3. Label all of the parts of the Box-Whisker plot. 4. Identify outliers if there are any. 
  2. 22 15 18 20 12 16 15 25 11 14 
  3. 35 26 2 22 37 42 40 29 24 
  4. 24 27 17 12 28 13 20 27 15 21 50  

Section 3: Normal Distribution Curve. 

  1. Label all of the parts of the Normal Distribution Curve Below. 

 

Section 4: Standard Deviation 

  1.  

Follow the steps below to find the standard deviation for the following data. 

12 18 24 7 15 12 9 10 13 21 Mean=_______________ Numbers Data - Mean Squared 

Total 

Mean of the differences Squared______________ 

Standard Deviation=_____________

Expert Solution
Step 1

“Since you have asked multiple questions, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.”

a)

The following procedure is used to construct a stem and leaf plot for the given data,

  • Enter the data into Minitab worksheet.
  • Select Graph, Stem and Leaf.
  • Under Variables, select the variable containing the temperature values.
  • Enter 10 for Increment.
  • Click OK.

Output:

Probability homework question answer, step 1, image 1

Thus, the stem and leaf plot is constructed for the given data.

Step 2

b)

The following procedure is used to construct a box and whisker plot,

  • Enter the data into Minitab worksheet.
  • Select Graph, Boxplot.
  • Under Variables, select the variable containing the data values.
  • Click OK.

Output:

Probability homework question answer, step 2, image 1

The lower and upper limits values for detecting the outliers are,

Probability homework question answer, step 2, image 2

Thus, the lower and upper limits values for detecting the outliers are -3.375 and 45.625.

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