3. Bromine, Br2 Consider the fragmentation of diatomic compounds. For example, 158Br2 will give a signal at 79 for 79Br and one at 79 for Br. Br has two naturally occurring isotopes, the 79 isotope and the 81 isotope. Determine the origin (formula) of each of the signals for the mass spectrum of molecular bromine. Example, 158Br2 is equal to 79Br79Br. Relative Abundance 90 80 70 60 50 30 20 10 D 79 81 158 160 162 62 Mass (amu) Figure 4. Mass Spectrum of Br. Mass Number Measurement (cm) Abundance Formula Calculations XXXX XXXX XXXX XXXX XXXX XXXX

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3. Bromine, Br2
Consider the fragmentation of diatomic compounds. For example, 158Br2 will give a
signal at 79 for 79Br and one at 79 for Br. Br has two naturally occurring isotopes, the
79 isotope and the 81 isotope. Determine the origin (formula) of each of the signals for
the mass spectrum of molecular bromine. Example, 158Br2 is equal to 79Br79Br.
Relative Abundance
90
80
70
60
50
30
20
10
D
79
81
158
160
162
62
Mass (amu)
Figure 4. Mass Spectrum of Br.
Mass Number
Measurement (cm) Abundance
Formula
Calculations
XXXX
XXXX
XXXX
XXXX
XXXX
XXXX
Transcribed Image Text:3. Bromine, Br2 Consider the fragmentation of diatomic compounds. For example, 158Br2 will give a signal at 79 for 79Br and one at 79 for Br. Br has two naturally occurring isotopes, the 79 isotope and the 81 isotope. Determine the origin (formula) of each of the signals for the mass spectrum of molecular bromine. Example, 158Br2 is equal to 79Br79Br. Relative Abundance 90 80 70 60 50 30 20 10 D 79 81 158 160 162 62 Mass (amu) Figure 4. Mass Spectrum of Br. Mass Number Measurement (cm) Abundance Formula Calculations XXXX XXXX XXXX XXXX XXXX XXXX
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