[References]Calculate AH for the reaction:2NH3 (g) + O2(g) → N2H4 (1) + H2O(1)given the following data:2NH3 (g) + 3N2O(g) → 4N2(g) + 3H2O(1) AH =–1010. kJN2O(9) + ЗH2(9) — N;Ha (1) + Hа0(1) ДН %3D — 317 kJN2H4 (1) + O2 (9) → N2(g)+2H20(1)ΔΗ--623 k.JНа (9) + О2(9) — Н,0(1)AH = -286 kJΔΗ-kJSubmit AnswerTry Another Version3 item attempts remaining

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2NH3 (g) + 02(9) → N2H4(1) + H20(1) given the following data: 2NH3 (g) + 3N20(g) → 4N2(9) + 3H2O(1) AH = -1010. kJ N20(g) + 3H2(g) → N½H4(1) + H2O(1) AH = -317 kJ N2H4 (1) + O2 (9) → N2(g) +2H2O(1) AH = -623 kJ H2 (9) + 02 (9) → H2O(1) AH = -286 kJ ΔΗ= kJ %D

2NH3 (g) + 02(9) → N2H4(1) + H20(1) given the following data: 2NH3 (g) + 3N20(g) → 4N2(9) + 3H2O(1) AH = -1010. kJ N20(g) + 3H2(g) → N½H4(1) + H2O(1) AH = -317 kJ N2H4 (1) + O2 (9) → N2(g) +2H2O(1) AH = -623 kJ H2 (9) + 02 (9) → H2O(1) AH = -286 kJ ΔΗ= kJ %D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

[References]
Calculate AH for the reaction:
2NH3 (g) + O2(g) → N2H4 (1) + H2O(1)
given the following data:
2NH3 (g) + 3N2O(g) → 4N2(g) + 3H2O(1) AH =–1010. kJ
N2O(9) + ЗH2(9) — N;Ha (1) + Hа0(1) ДН %3D — 317 kJ
N2H4 (1) + O2 (9) → N2(g)+2H20(1)
ΔΗ--623 k.J
На (9) + О2(9) — Н,0(1)
AH = -286 kJ
ΔΗ-
kJ
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