Given the following data 2 CIF (g) + O₂(g) → Cl₂ O(g) + F₂O(g) 2 CIF3 (9) +202(g) → Cl₂ O(g) + 3F₂O(g) 2F2(g) + O₂(g) →2F₂O(g) calculate A H for the reaction AH= CIF (g) + F₂ (g) → CIF3 (9) kj AH 167.4 kJ Δ Η = 341.4 kJ AH-43.4 kJ
Types of Chemical Bonds
The attractive force which has the ability of holding various constituent elements like atoms, ions, molecules, etc. together in different chemical species is termed as a chemical bond. Chemical compounds are dependent on the strength of chemical bonds between its constituents. Stronger the chemical bond, more will be the stability in the chemical compounds. Hence, it can be said that bonding defines the stability of chemical compounds.
Polarizability In Organic Chemistry
Polarizability refers to the ability of an atom/molecule to distort the electron cloud of neighboring species towards itself and the process of distortion of electron cloud is known as polarization.
Coordinate Covalent Bonds
A coordinate covalent bond is also known as a dative bond, which is a type of covalent bond. It is formed between two atoms, where the two electrons required to form the bond come from the same atom resulting in a semi-polar bond. The study of coordinate covalent bond or dative bond is important to know about the special type of bonding that leads to different properties. Since covalent compounds are non-polar whereas coordinate bonds results always in polar compounds due to charge separation.
![### Given the following data
1. \(2 \text{ClF}(g) + O_2(g) \rightarrow \text{Cl}_2O(g) + \text{F}_2O(g)\)
\(\quad \Delta H = 167.4 \, \text{kJ}\)
2. \(2 \text{ClF}_3(g) + 2 O_2(g) \rightarrow \text{Cl}_2O(g) + 3\text{F}_2O(g)\)
\(\quad \Delta H = 341.4 \, \text{kJ}\)
3. \(2 \text{F}_2(g) + O_2(g) \rightarrow 2 \text{F}_2O(g)\)
\(\quad \Delta H = -43.4 \, \text{kJ}\)
### Calculate \(\Delta H\) for the reaction
\(\text{ClF}(g) + \text{F}_2(g) \rightarrow \text{ClF}_3(g)\)
\[
\Delta H = \_\_\_\_\_ \, \text{kJ}
\]
### Explanation
- **Equation 1:** Describes the reaction where 2 moles of chlorine monofluoride (ClF) react with oxygen (O2) to form chlorine monoxide (Cl2O) and fluoro monoxide (F2O) with an enthalpy change (\(\Delta H\)) of 167.4 kJ.
- **Equation 2:** Describes the reaction where 2 moles of chlorine trifluoride (ClF3) react with 2 moles of oxygen (O2) to form chlorine monoxide (Cl2O) and 3 moles of fluoro monoxide (F2O) with an enthalpy change (\(\Delta H\)) of 341.4 kJ.
- **Equation 3:** Describes the reaction where 2 moles of difluorine (F2) react with oxygen (O2) to form 2 moles of fluoro monoxide (F2O) with an enthalpy change (\(\Delta H\)) of -43.4 kJ.
You are tasked with calculating the enthalpy change (\(\Delta H\)) for the reaction where chlorine monofluoride (ClF) reacts with dif](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F216d8975-823a-443e-8abc-06f056adfa09%2Fa723921b-8a58-437b-a092-542d64777d61%2F6tfcaws_processed.png&w=3840&q=75)
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