Consider the following two reactions and the corresponding enthalpy changes: CH4(g) +2 O2(g)→ CO2(g)+2 H2O(I), ΔΗ 2 CH3OH(I), ΔΗ2 2 CH4(g) + O2(g) - Express the enthalpy change for the third reaction 2CH3OH(I)+3O2(g)- 2CO2(g) + 4H2O(g), ΔΗ3 in terms of ΔΗ1 and ΔΗ2· Ο ΔΗ3-2ΔΗ - ΔΗ = Ο ΔΗ3 = ΔΗ1 + ΔΗ2 ΟΔΗ-ΔΗ - ΔΗ Ο ΔΗ3 = 2ΔΗ1 +ΔΗ2 ΟΔΗ;=2ΔΗ - ΔΗ

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Chapter6: Thermochemisty
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Problem 6.81QP: Compounds with carboncarbon double bonds, such as ethylene, C2H4, add hydrogen in a reaction called...
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Consider the following two reactions and the corresponding enthalpy changes:
CH4(g) +2 O2(g)→ CO2(g)+2 H2O(I), ΔΗ
2 CH4(g) + O2(g) 2 CH3OH(I), ΔΗ2
Express the enthalpy change for the third reaction
2CH3OH(I)+3O2(g)-2CO2(g) + 4H2O(g), ΔΗ
in terms of ΔΗ1 and ΔΗ2·
Ο ΔΗ3=2ΔΗ2 - ΔΗ
Ο ΔΗ = ΔΗ + ΔΗ
Ο
ΔΗ3=ΔΗ - ΔΗ2
Ο
ΔΗ3 = 2ΔΗ1 +ΔΗ2
ΔΗ3 = 2ΔΗ - ΔΗ
Transcribed Image Text:Consider the following two reactions and the corresponding enthalpy changes: CH4(g) +2 O2(g)→ CO2(g)+2 H2O(I), ΔΗ 2 CH4(g) + O2(g) 2 CH3OH(I), ΔΗ2 Express the enthalpy change for the third reaction 2CH3OH(I)+3O2(g)-2CO2(g) + 4H2O(g), ΔΗ in terms of ΔΗ1 and ΔΗ2· Ο ΔΗ3=2ΔΗ2 - ΔΗ Ο ΔΗ = ΔΗ + ΔΗ Ο ΔΗ3=ΔΗ - ΔΗ2 Ο ΔΗ3 = 2ΔΗ1 +ΔΗ2 ΔΗ3 = 2ΔΗ - ΔΗ
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