Determine the enthalpy of reaction for 2CH2(g) → C₂H4(g) + 2H₂(g) using the equations: 2C₂H6(g) + 70₂(g) → 4CO₂(g) + 6H₂O(l) AH° = -3120.8 kJ/mol CH₂(g) + 20₂(g) → CO₂(g) + 2H₂O(1) AH° = -890.3 kJ/mol C₂H4(g) + H₂(g) → C₂H6(g) AH° = -136.3 kJ/mol H₂ + 1/2O2(g) → H₂O(1) AH° = −285.8 kJ/ mol
Determine the enthalpy of reaction for 2CH2(g) → C₂H4(g) + 2H₂(g) using the equations: 2C₂H6(g) + 70₂(g) → 4CO₂(g) + 6H₂O(l) AH° = -3120.8 kJ/mol CH₂(g) + 20₂(g) → CO₂(g) + 2H₂O(1) AH° = -890.3 kJ/mol C₂H4(g) + H₂(g) → C₂H6(g) AH° = -136.3 kJ/mol H₂ + 1/2O2(g) → H₂O(1) AH° = −285.8 kJ/ mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Determine the enthalpy of reaction for
2CH₂(g) → C₂H₂(g) + 2H₂(g) using the
equations:
2C₂H6(g) + 702(g) → 4CO₂(g) + 6H₂O(1)
AH° -3120.8 kJ/mol
=
CH4(g) + 20₂(g) → CO₂(g) + 2H₂O (1) AH°
= -890.3 kJ/mol
C₂H4(g) + H₂(g) → C₂H6(g) AH° = -136.3
kJ/mol
H₂ + 1/2O₂(g) → H₂O(1) AH° = -285.8 kJ/
mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2a3647a4-d4e3-4a0d-a2cb-bcbd815e9f9e%2F3f389099-ffe0-483c-a2fb-8e0392f30acb%2F615d5exh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the enthalpy of reaction for
2CH₂(g) → C₂H₂(g) + 2H₂(g) using the
equations:
2C₂H6(g) + 702(g) → 4CO₂(g) + 6H₂O(1)
AH° -3120.8 kJ/mol
=
CH4(g) + 20₂(g) → CO₂(g) + 2H₂O (1) AH°
= -890.3 kJ/mol
C₂H4(g) + H₂(g) → C₂H6(g) AH° = -136.3
kJ/mol
H₂ + 1/2O₂(g) → H₂O(1) AH° = -285.8 kJ/
mol
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