Use the thermochemical equations shown below to determine the enthalpy for this reaction: 2 H2O(g) + 2 Cl2(g) →4 HCl (9) + O2(g) ΔΗ xn Information: COCI 2(g) + H2O(l) → CH2Cl2(1) + O2(g) AH = 19 kJ H2O(g) →H2O(l) AH = -44 kJ HCI (g) 1/2 H2(g) +1/2 Cl2(g) AH = 92 kJ CH2Cl2(1) + H2(g) + 3/2 O2(g) → COCI 2(g) + 2 H2O (1) AH=-161k]
Use the thermochemical equations shown below to determine the enthalpy for this reaction: 2 H2O(g) + 2 Cl2(g) →4 HCl (9) + O2(g) ΔΗ xn Information: COCI 2(g) + H2O(l) → CH2Cl2(1) + O2(g) AH = 19 kJ H2O(g) →H2O(l) AH = -44 kJ HCI (g) 1/2 H2(g) +1/2 Cl2(g) AH = 92 kJ CH2Cl2(1) + H2(g) + 3/2 O2(g) → COCI 2(g) + 2 H2O (1) AH=-161k]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Use the thermochemical equations shown below to determine the enthalpy for this reaction: 2 H2O(g) + 2 Cl2(g) →4 HCl (9) + O2(g)
ΔΗ
xn
Information:
COCI 2(g) + H2O(l) → CH2Cl2(1) + O2(g)
AH = 19 kJ
H2O(g) →H2O(l)
AH = -44 kJ
HCI (g) 1/2 H2(g) +1/2 Cl2(g)
AH = 92 kJ
CH2Cl2(1)
+ H2(g) + 3/2 O2(g) → COCI 2(g) + 2 H2O (1)
AH=-161k]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b232b58-865f-456f-bcb4-7c3b5bfb74bd%2Fe5452b4d-c569-45bd-bf08-21a666ce225a%2Ffxfc0nb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the thermochemical equations shown below to determine the enthalpy for this reaction: 2 H2O(g) + 2 Cl2(g) →4 HCl (9) + O2(g)
ΔΗ
xn
Information:
COCI 2(g) + H2O(l) → CH2Cl2(1) + O2(g)
AH = 19 kJ
H2O(g) →H2O(l)
AH = -44 kJ
HCI (g) 1/2 H2(g) +1/2 Cl2(g)
AH = 92 kJ
CH2Cl2(1)
+ H2(g) + 3/2 O2(g) → COCI 2(g) + 2 H2O (1)
AH=-161k]
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