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25 + 30, → 250, 11. How many moles of S is needed to form 2 moles of SO ? А. 1 В. 2 С. 3 D. 6

25 + 30, → 250, 11. How many moles of S is needed to form 2 moles of SO ? А. 1 В. 2 С. 3 D. 6

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Refer to the chemical equation below to answer questions 11-13. 25 + 30, → 250, 11. How many moles of S is needed to form 2 moles of SO ? 3. А. 1 В. 2 С.3 D. 6 12. How many moles of O, are needed to give 4 moles of SO ? 2. А. 3 В. 2 С.6 D. 4 13. How many moles of oxygen atoms are there in 1 mole of oxygen molecule? A. 6 В. 3 14. In a chemical reaction, the mass of the products is С. 1 D. 2 A. equal to the mass of the reactants B. greater than the mass of the reactants C. less than the mass of the reactants. D. undetermined 15. Which of these is incorrect interpretation of this balanced equation? A. 2 g 5 +3g0, →28 S0, B. 2 atoms S+ 3 molecules 0 molecules SO, 3. C. 2 moles S+ 3 moles O2 moles SO, 3. D. All
Transcribed Image Text:Refer to the chemical equation below to answer questions 11-13. 25 + 30, → 250, 11. How many moles of S is needed to form 2 moles of SO ? 3. А. 1 В. 2 С.3 D. 6 12. How many moles of O, are needed to give 4 moles of SO ? 2. А. 3 В. 2 С.6 D. 4 13. How many moles of oxygen atoms are there in 1 mole of oxygen molecule? A. 6 В. 3 14. In a chemical reaction, the mass of the products is С. 1 D. 2 A. equal to the mass of the reactants B. greater than the mass of the reactants C. less than the mass of the reactants. D. undetermined 15. Which of these is incorrect interpretation of this balanced equation? A. 2 g 5 +3g0, →28 S0, B. 2 atoms S+ 3 molecules 0 molecules SO, 3. C. 2 moles S+ 3 moles O2 moles SO, 3. D. All
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