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5. Consider heptane -> toluene + hydrogen C7H16 (g) → C6H5CH3(g) + 4H₂(g) Basis: 1 mol C₂H16 1 mol C₂H16 400°C Q (kJ/mol) Cp heptane = 0.276 kJ/mol Cp toluene = 0.161 kJ/mol 1 mol C6H,CH3 4 mol H₂ 400° C

5. Consider heptane -> toluene + hydrogen C7H16 (g) → C6H5CH3(g) + 4H₂(g) Basis: 1 mol C₂H16 1 mol C₂H16 400°C Q (kJ/mol) Cp heptane = 0.276 kJ/mol Cp toluene = 0.161 kJ/mol 1 mol C6H,CH3 4 mol H₂ 400° C

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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5. Consider heptane -> toluene + hydrogen C7H16 (g) → C6H5CH3(g) + 4H₂(g) Basis: 1 mol C7H16 1 mol C7H16 400°C Q (kJ/mol) Cp heptane = 0.276 kJ/mol Cp toluene = 0.161 kJ/mol What is Q? 1 mol C6H5CH3 4 mol H₂ 400° C F
Transcribed Image Text:5. Consider heptane -> toluene + hydrogen C7H16 (g) → C6H5CH3(g) + 4H₂(g) Basis: 1 mol C7H16 1 mol C7H16 400°C Q (kJ/mol) Cp heptane = 0.276 kJ/mol Cp toluene = 0.161 kJ/mol What is Q? 1 mol C6H5CH3 4 mol H₂ 400° C F
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