Question 4 The volume-temperature relationship for liquid acetone in Perry's Chemical Engineers' Handbook 7th ed p. 2-131 (t is the temperature in °C) V = Vo(1 + a₁t+ a₂t² + a3t³) = Vo 1.228 x 10-³ m³/kg, a₁ = 1.3240 x10-³ a₂ = 3.8090 x 10-6, a3 = - 0.87983 x 10-8 (3H),, and (3), T Calculate (3) (35) at T = 300 K a

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A: Temperature: 1600 K Pressure : 50kPa Moles Of H2 = 0.4 Moles of O2 = 0.6

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A: Please select text to grab.

Q: "he vapor pressure of liquid ethyl acetate, CH3C0OC,H5, is 100. mm Hg at 300 K. A sample of…

A: VP (liquid ethyl acetate ) = 100mmHg at T= 300K P1 = 76 mlV1 = 591 mlV2 = 308 ml P2 = ?

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A: To be proved,

Q: There's a copper calorimeter container with the mass 0.2 kg and has 0.32 kg of H2O and also 0.036 kg…

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