I posted this question before but didn't get the explanation, can I get an explanation on how to get fugacity coefficient using the written formula I attached, thanks.
I posted this question before but didn't get the explanation, can I get an explanation on how to get fugacity coefficient using the written formula I attached, thanks.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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I posted this question before but didn't get the explanation, can I get an explanation on how to get fugacity coefficient using the written formula I attached, thanks.
Transcribed Image Text:O
ㅇㅇ
In / fi (pure)
미
P
T
ㅣ
|
|
2-1 dp
렇
Transcribed Image Text:4
@85°C -
A unit-operation in the manufacture of a light oil produces the oil at 200 K and 30 bar
along with some CH4 gas. At equilibrium, this binary system of CH4 (1) and light oil (2)
consists of a vapour phase containing 95 mol % CH4 and a liquid phase that contains the
oil and a small amount of dissolved CH4. The fugacity of CH4 in the liquid phase at 200 K
is given by Henry's law with the constant k₁= 200 bar. Determine the mole fraction of
CH4 in the liquid phase.
0.989
Assume that CH4 in the vapour phase obeys the Lewis-Randall rule. The P-V-T
behaviour of CH4 is described by the truncated virial equation:
Z = 1 + BP/RT
which may be used to calculate the thermodynamic properties of pure CH4. The second
virial coefficient, B = -105 cm³ mol-1 for CH4 at 200 K.
given
(4 (1)
P= 36 ber
oil (2)
T= 200k
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