I need help with this. Here is the information and data needed. Record your slope and correlation coefficient, and intercept form your Part 1 graph Y = Absorbance = 447.6 nm B = Y Intercept = 0.006465 M = slope 2838   K = concentration of (FeSCN) So (FeSCN) equilibrium is = to : 447.6 – (0.006465) / 2838 = 0.1577144239   Equation of best fit line ____________________________________________________   Part II Table 2. Raw data collected Solution Temperature (°C) Absorbance 1 Room temperature (°C) 0.223 2 Room temperature (°C) 0.330   3 Room temperature (°C) 0.448   4 Room temperature (°C) 0.543   Calculate the equilibrium concentration of Fe(SCN)2+ for each solution 1-4 using the equation from the line on your graph obtained in Part I. Enter your results in Table 3.  Show at least one sample calculation

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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I need help with this. Here is the information and data needed.

  1. Record your slope and correlation coefficient, and intercept form your Part 1 graph

Y = Absorbance = 447.6 nm

B = Y Intercept = 0.006465

M = slope 2838

 

K = concentration of (FeSCN)

So (FeSCN) equilibrium is = to : 447.6 – (0.006465) / 2838 = 0.1577144239

 

Equation of best fit line ____________________________________________________

 

Part II

Table 2. Raw data collected

Solution

Temperature (°C)

Absorbance

1

Room temperature (°C)

0.223

2

Room temperature (°C)

0.330

 

3

Room temperature (°C)

0.448

 

4

Room temperature (°C)

0.543

 

  1. Calculate the equilibrium concentration of Fe(SCN)2+ for each solution 1-4 using the equation from the line on your graph obtained in Part I. Enter your results in Table 3.  Show at least one sample calculation.
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