Question : consider the 2nd virial equation of state 7 = 1 + = = · The second virial cofficient of mixture is given by for (0₂ (1) and CH 3 Br (2) at 2971 and 500 kper :- B₁1 = -394·1x106m²/mal B=X₁ B₁ + 2X₁X2B₁2 +2²₂ B ₂ 2 42 B12=-567-3X16 m/mot B 23=-411x6 m²/mal al Explain the physical meaning for the 2nd virial cofficient. bi Determine the value of the and virial coffierent, B. e) petermine the motor volume V.

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