1. Based on the figure below: ng(mol) 0.983 DA 0.017 W(V) 100 mol 10.983 DA 10.017 W(v) n;(mol) nz(mol) AIR nalmol) 0.960 DA 0.040 W(v) 0.977 DA COND. 0.983 DA 0.017 Wtv) 0.023 W(v) DA = dry air W = water nylmol W1)) Solve for the Following: a. ni or Fresh Feed (F) b. n3 or Water Condensed (W) c. ns or Recycle (R)
1. Based on the figure below: ng(mol) 0.983 DA 0.017 W(V) 100 mol 10.983 DA 10.017 W(v) n;(mol) nz(mol) AIR nalmol) 0.960 DA 0.040 W(v) 0.977 DA COND. 0.983 DA 0.017 Wtv) 0.023 W(v) DA = dry air W = water nylmol W1)) Solve for the Following: a. ni or Fresh Feed (F) b. n3 or Water Condensed (W) c. ns or Recycle (R)
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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1. Kindly solve this and show your complete solution.
![1. Based on the figure below:
ng(mol)
0.983 DA
0.017 W(v)
ny(mol)
0.960 DA .-
0.040 W(v):
100 mol
10.983 DA
0.017 Wv)
ng{mol)
AIR
nalmol)
0.977 DA
0.023 W(v)
COND.
0.983 DA
0.017 Wtv)
DA = dry air
W = water
nylmol W1)]
Solve for the Following:
a. ni or Fresh Feed (F)
b. n3 or Water Condensed (W)
c. ns or Recycle (R)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faaa21af8-1551-4867-91e4-b6322380457c%2Fb36fe049-5fd5-4a4e-aa7f-4ce135a3e1ab%2Fkadunti_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Based on the figure below:
ng(mol)
0.983 DA
0.017 W(v)
ny(mol)
0.960 DA .-
0.040 W(v):
100 mol
10.983 DA
0.017 Wv)
ng{mol)
AIR
nalmol)
0.977 DA
0.023 W(v)
COND.
0.983 DA
0.017 Wtv)
DA = dry air
W = water
nylmol W1)]
Solve for the Following:
a. ni or Fresh Feed (F)
b. n3 or Water Condensed (W)
c. ns or Recycle (R)
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