23:12 Chegg content://org.teleg + 5G 5G 80% New question A feed of 60 mol% methanol in water at 1 atm is to be separated by dislation into a liquid distilate containing 98 mol% methanol and a bottom containing 96 mol% water. Enthalpy and equilibrium data for the mixture at 1 atm are given in Table Q2 below. Ask an expert (a) Devise a procedure, using the enthalpy-concentration diagram, to determine the minimum number of equilibrium trays for the condition of total reflux and the required separation. Show individual equilibrium trays using the the lines. Comment on why the value is Independent of the food condition. Recent My stuff Mol% MeOH, Saturated vapour Table Q2 Methanol-water vapour liquid equilibrium and enthalpy data for 1 atm Enthalpy above C˚C Equilibrium dala Mol% MeOH in Saturated liquid TC kJ mol T. "Chk kot) Liquid T, "C 0.0 100.0 48.195 100.0 7.536 0.0 0.0 100.0 5.0 90.9 47,730 928 7,141 2.0 13.4 96.4 Perks 10.0 97.7 47,311 87.7 8,862 4.0 23.0 93.5 16.0 96.2 46,892 84.4 6,029 6.0 30.4 91.2 20.0 94.8 48.520 6,420 36.5 89.3 30.0 91.6 45,683 78.0 6.094 100 41.8 87.7 40.0 44915 75.3 5.906 150 51.7 844 Learning lab 50.0 84.9 44.124 73.1 5,745 200 60.0 80.9 43,380 71.2 5.006 30.0 579 81.7 06.5 78.0 70.0 76.6 69.3 5,513 40.0 72.9 75.3 800 72.2 41,821 5,420 50.0 779 73.1 900 68.1 41.124 5,327 60.0 825 712 100.0 64.5 40.449 64.5 5.234 700 87.0 69.3 80.0 91.5 67.6 NB. MeOH methyl alcohol 90.0 95.8 66.0 95.0 97.9 65.0 100.0 100.0 64.5 Show Image Transcript Here's the best solution from Chegg's library Solution Answered by a Chemical engineering expert 31 SOLUTION:As per the given data The bubble point temperatures of distillate and bottoms are needed Ans(1): Given that, the mole fraction of methanol in distillate (xD) = 0.98 That is molefraction in vapour And also given that, corresponding temperatures for te given molefraction data as For 0.979 molefraction of methanol in vapour. corresponding temperature is 650C For 1 molefraction of methanol in vapour, corresponding temperature is 64.5deg C So, for 0.98 molefraction of methanol in vapour. the corresponding bubble point temperature is T Therefore, T-64.98deg C Ans(2): Given that, the mole fraction of methanol in bottoms (xw) = 1-0.96 0.04 (Since, the mole fraction of water in bottoms is 0.96) For 0.04 molefraction of methanol in bottoms (liquid), corresponding bubble point temperature is 93.5deg C Any follow-up questions? EN-US V Code age Preferences instant responses come from subject matter exports, Al models trained on Chogg's learning content, or Open Automated chats are recorded & may be used to improve your experience. Please don't share sensitive into 0

Operations Research : Applications and Algorithms
4th Edition
ISBN:9780534380588
Author:Wayne L. Winston
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Chapter11: Nonlinear Programming
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23:12
Chegg
content://org.teleg +
5G
5G
80%
New question
A feed of 60 mol% methanol in water at 1 atm is to be separated by dislation into a
liquid distilate containing 98 mol% methanol and a bottom containing 96 mol% water.
Enthalpy and equilibrium data for the mixture at 1 atm are given in Table Q2 below.
Ask an expert
(a)
Devise a procedure, using the enthalpy-concentration diagram, to determine the
minimum number of equilibrium trays for the condition of total reflux and the
required separation. Show individual equilibrium trays using the the lines.
Comment on why the value is Independent of the food condition.
Recent
My stuff
Mol%
MeOH,
Saturated vapour
Table Q2 Methanol-water vapour liquid equilibrium and enthalpy data for 1 atm
Enthalpy above C˚C
Equilibrium dala
Mol% MeOH in
Saturated liquid
TC kJ mol T. "Chk kot)
Liquid
T, "C
0.0 100.0
48.195
100.0
7.536
0.0
0.0
100.0
5.0 90.9
47,730
928
7,141
2.0
13.4
96.4
Perks
10.0 97.7
47,311
87.7
8,862
4.0
23.0
93.5
16.0 96.2 46,892
84.4
6,029
6.0
30.4
91.2
20.0 94.8
48.520
6,420
36.5
89.3
30.0 91.6
45,683
78.0
6.094
100
41.8
87.7
40.0
44915
75.3
5.906
150
51.7
844
Learning lab
50.0 84.9
44.124
73.1
5,745
200
60.0
80.9
43,380
71.2
5.006
30.0
579
81.7
06.5
78.0
70.0 76.6
69.3
5,513
40.0
72.9 75.3
800 72.2
41,821
5,420
50.0
779
73.1
900 68.1
41.124
5,327
60.0 825
712
100.0
64.5
40.449
64.5
5.234
700
87.0
69.3
80.0
91.5
67.6
NB. MeOH methyl alcohol
90.0
95.8
66.0
95.0
97.9
65.0
100.0
100.0
64.5
Show Image Transcript
Here's the best solution from Chegg's library
Solution
Answered by a Chemical engineering expert
31
SOLUTION:As per the given data
The bubble point temperatures of distillate and bottoms are
needed
Ans(1):
Given that, the mole fraction of methanol in distillate (xD) =
0.98
That is molefraction in vapour
And also given that, corresponding temperatures for te given
molefraction data as
For 0.979 molefraction of methanol in vapour.
corresponding temperature is 650C
For 1 molefraction of methanol in vapour, corresponding
temperature is 64.5deg C
So, for 0.98 molefraction of methanol in vapour.
the corresponding bubble point temperature is T
Therefore, T-64.98deg C
Ans(2):
Given that, the mole fraction of methanol in bottoms (xw) =
1-0.96 0.04
(Since, the mole fraction of water in bottoms is 0.96)
For 0.04 molefraction of methanol in bottoms (liquid),
corresponding bubble point temperature is 93.5deg C
Any follow-up questions?
EN-US V
Code
age Preferences
instant responses come from subject matter exports, Al models trained on Chogg's learning content, or Open
Automated chats are recorded & may be used to improve your experience. Please don't share sensitive into
0
Transcribed Image Text:23:12 Chegg content://org.teleg + 5G 5G 80% New question A feed of 60 mol% methanol in water at 1 atm is to be separated by dislation into a liquid distilate containing 98 mol% methanol and a bottom containing 96 mol% water. Enthalpy and equilibrium data for the mixture at 1 atm are given in Table Q2 below. Ask an expert (a) Devise a procedure, using the enthalpy-concentration diagram, to determine the minimum number of equilibrium trays for the condition of total reflux and the required separation. Show individual equilibrium trays using the the lines. Comment on why the value is Independent of the food condition. Recent My stuff Mol% MeOH, Saturated vapour Table Q2 Methanol-water vapour liquid equilibrium and enthalpy data for 1 atm Enthalpy above C˚C Equilibrium dala Mol% MeOH in Saturated liquid TC kJ mol T. "Chk kot) Liquid T, "C 0.0 100.0 48.195 100.0 7.536 0.0 0.0 100.0 5.0 90.9 47,730 928 7,141 2.0 13.4 96.4 Perks 10.0 97.7 47,311 87.7 8,862 4.0 23.0 93.5 16.0 96.2 46,892 84.4 6,029 6.0 30.4 91.2 20.0 94.8 48.520 6,420 36.5 89.3 30.0 91.6 45,683 78.0 6.094 100 41.8 87.7 40.0 44915 75.3 5.906 150 51.7 844 Learning lab 50.0 84.9 44.124 73.1 5,745 200 60.0 80.9 43,380 71.2 5.006 30.0 579 81.7 06.5 78.0 70.0 76.6 69.3 5,513 40.0 72.9 75.3 800 72.2 41,821 5,420 50.0 779 73.1 900 68.1 41.124 5,327 60.0 825 712 100.0 64.5 40.449 64.5 5.234 700 87.0 69.3 80.0 91.5 67.6 NB. MeOH methyl alcohol 90.0 95.8 66.0 95.0 97.9 65.0 100.0 100.0 64.5 Show Image Transcript Here's the best solution from Chegg's library Solution Answered by a Chemical engineering expert 31 SOLUTION:As per the given data The bubble point temperatures of distillate and bottoms are needed Ans(1): Given that, the mole fraction of methanol in distillate (xD) = 0.98 That is molefraction in vapour And also given that, corresponding temperatures for te given molefraction data as For 0.979 molefraction of methanol in vapour. corresponding temperature is 650C For 1 molefraction of methanol in vapour, corresponding temperature is 64.5deg C So, for 0.98 molefraction of methanol in vapour. the corresponding bubble point temperature is T Therefore, T-64.98deg C Ans(2): Given that, the mole fraction of methanol in bottoms (xw) = 1-0.96 0.04 (Since, the mole fraction of water in bottoms is 0.96) For 0.04 molefraction of methanol in bottoms (liquid), corresponding bubble point temperature is 93.5deg C Any follow-up questions? EN-US V Code age Preferences instant responses come from subject matter exports, Al models trained on Chogg's learning content, or Open Automated chats are recorded & may be used to improve your experience. Please don't share sensitive into 0
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