3.| The following program undergoes scope checking using a stack of symbol tables:1.void main() {2.5.6.7.8.int a; int b%3B int c%;Bif (a == b) {float c%;Bfor (int c = 1; c <10%;B c++ ) {cout << a;9.}10.}11.12.13.int a;else {} /* else */ } /* main */(a) [10] Draw the symbol tables created for this program as follows: List in each sym-bol table all the identifiers in that scope as pairs (identifier,type). Then draw the links(pointers) between the symbol tables that establish the stack structure.(b) [5] Let the scope checking algorithm process line 8 of the program. Identify in youranswer to the previous question the symbol table corresponding to the current scope aswell as the symbol tables corresponding to all the open scopes. Explain then how arethe symbol tables inspected to obtain the type of variable a.

(a) Symbol Tables and Stack StructureHere is the list of symbol tables created for the given…

Answered: 3. | The following program undergoes…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Deal or No Deal? Code in C language
Write c++ code for this matrix
#include<bits/stdc++.h>#include<math.h>using namespace std; class TotalResistance{double series_res,parallel_res,sp_res;public:TotalResistance(){series_res=parallel_res=sp_res=0;}void seriesResistance(double resistance[],int n);void parallelResistance(double resistance[],int n);void spResistance(double resistance[],int n);};void TotalResistance::seriesResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];cout<<"Total Resistance in series is: "<<series_res<<endl;}void TotalResistance::parallelResistance(double resistance[],int n){double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in parallel is: "<<parallel_res<<endl;}void TotalResistance::spResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in…
#include<bits/stdc++.h>#include<math.h>using namespace std; class TotalResistance{double series_res,parallel_res,sp_res;public:TotalResistance(){series_res=parallel_res=sp_res=0;}void seriesResistance(double resistance[],int n);void parallelResistance(double resistance[],int n);void spResistance(double resistance[],int n);};void TotalResistance::seriesResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];cout<<"Total Resistance in series is: "<<series_res<<endl;}void TotalResistance::parallelResistance(double resistance[],int n){double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in parallel is: "<<parallel_res<<endl;}void TotalResistance::spResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in…
C++ Programming Problem: Newton is a brilliant mathematician and solving triangles problems fascinates him. Today he is given a sequence of positive integers V1, V2, ., VN. You must choose three elements Vx, Vy, Vz (x, y, z is vertices) such that the triangle formed have these properties: |XY|= Vz, |XZ|=Vy, |YZ|=Vx and the angle |ZYXZ|= 0 satisfies cose2P/Q, where 0 should be maximum possible. Find any such triangle or determine that it does not exist. Develop a C++ code which prints the value of x, y, z in a single line and print "Invalid" if not possible. Test Case: 412 9765 Result: 324
1、Counting Primitive Operations void STRAITMAXMIN(A,n,max,min) //Set the maximum value in A to max and the minimum value to min { int i,n max=min=A[1] for i=2 to n { if A[i]> max max=A[i]; if A[i]< min min=A[i]; } }
Consider the producer-consumer problem where the producer produces items to be consumed by the consumer. A solution of the problem is to be implemented using threads. The main process will run producer and consumer as two different threads. The producer will put the items it generates into a buffer of length 15. The consumer reads the elements of the buffer to get the items. A solution is given below. Each item produced and consumed are also printed to the screen. Run the program several times and find a sample run when the items produced are not correctly consumed. Explain why the program does not always work correctly.
8.
PROGRAMMING LANGUAGE: C++ SUBJECT: OOP Task: Find errors in the following code and rewrite a correct version of code with outputs. #include <iostream> using namespace std; class CRectangle { int width. height; public: void set_values (int, int); int area () {return (width * height);} }; void CRectangle::set_values (int a, int b) { width = a; height = b; } int main () { CRectangle a,*b,*c; c= a; a.set_values (1,2); b= new CRectangle; c=&b; c->set_values (3,4); cout << "a area: " << c->area() << endl;// cout << "*b area: " << a.area() << endl;// c->set_values (5,6); cout << "*b area: " << b.area() << endl;// delete b; return 0; }
// add.ll define void @add(i32* %ptr1, i32* %ptr2, i32* %val) {ret void} Fill add.ll function to do the following operation: void add(int *ptr1, int *ptr2, int *val) { *ptr1 += *val; *ptr2 += *val; } This is the full question. It is related to LLVM. If it's going to help there is one more code given which is: #include <stdio.h> void add(int *ptr1, int *ptr2, int *val); int main(int argc, char **argv) {FILE *f = fopen(argv[1], "r");int a, b, c;fscanf(f, "%d %d %d", &a, &b, &c);add(&a, &b, &c);printf("%d %d\n", a, b);fclose(f); return 0;}
C++ Exercise
#6

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