21A 302 ww 120½ ✓ 18 V 2A (b) (i) From mesh 1; Applying KVL 21A-36-12(4-(2)-8cc-(3)=0 ⇒ 2IA-236, +126+863 =0 From 5A Current Source, connected between. nesh 3 and mesh 4; 13-14=5 (iii) Apply KVL in mesh 1; ww 802 ⇒>> 2IA = 231,-1262-863 100 3 5 A 502 IA = 23 c; -66-413 E2 IA a) Around which mesh currents can KVL be applied? b) Using the variables i1, 12, 13, and 14 for the mesh currents: i) Express lA in terms of the mesh currents ii) Write the equations for the mesh currents from the current sources iii) Apply KVL to the loop(s) identified in step i iv) Write the equation relating the mesh currents using the simplest superloop ✓ Screenshot 202... => Also from mesh 4; IA = (4 (b) (1) Equations from current Sources: from 2A current source in mesh 2: 2=-2A 21A-36-12CC-1)-8(c;-(3)=0 23 c; - 1262-8 13 = 21A (iv) Since there is a current source of 5A in common branch of mesh 3 and mesh4. KVL can not be applied to individual mesh 3 and mesti4. Forming superloop using mesh 3 and mesh 4 and applying KVL: -1063-8 (3-1)-18-514= =0 86-1863-564 = 18 A+ V+ A- V- -1.586 A 10 247.216 mA 12 2A 5A -5.247 A t = 7.635 s time step 5 us
21A 302 ww 120½ ✓ 18 V 2A (b) (i) From mesh 1; Applying KVL 21A-36-12(4-(2)-8cc-(3)=0 ⇒ 2IA-236, +126+863 =0 From 5A Current Source, connected between. nesh 3 and mesh 4; 13-14=5 (iii) Apply KVL in mesh 1; ww 802 ⇒>> 2IA = 231,-1262-863 100 3 5 A 502 IA = 23 c; -66-413 E2 IA a) Around which mesh currents can KVL be applied? b) Using the variables i1, 12, 13, and 14 for the mesh currents: i) Express lA in terms of the mesh currents ii) Write the equations for the mesh currents from the current sources iii) Apply KVL to the loop(s) identified in step i iv) Write the equation relating the mesh currents using the simplest superloop ✓ Screenshot 202... => Also from mesh 4; IA = (4 (b) (1) Equations from current Sources: from 2A current source in mesh 2: 2=-2A 21A-36-12CC-1)-8(c;-(3)=0 23 c; - 1262-8 13 = 21A (iv) Since there is a current source of 5A in common branch of mesh 3 and mesh4. KVL can not be applied to individual mesh 3 and mesti4. Forming superloop using mesh 3 and mesh 4 and applying KVL: -1063-8 (3-1)-18-514= =0 86-1863-564 = 18 A+ V+ A- V- -1.586 A 10 247.216 mA 12 2A 5A -5.247 A t = 7.635 s time step 5 us
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
Answer should be i1= -1.5A i2=-2A i3=247 mA i4=-5.24A When doing the matrix which I can't find my error. As you can see in the diagram.
Transcribed Image Text:21A
302
ww
120½
✓ 18 V
2A
(b) (i)
From mesh 1; Applying KVL
21A-36-12(4-(2)-8cc-(3)=0
⇒ 2IA-236, +126+863
=0
From 5A Current Source, connected between.
nesh 3 and mesh 4;
13-14=5
(iii) Apply KVL in mesh 1;
ww
802
⇒>>
2IA = 231,-1262-863
100 3
5 A
502
IA = 23 c; -66-413
E2
IA
a) Around which mesh currents can KVL be applied?
b) Using the variables i1, 12, 13, and 14 for the mesh currents:
i) Express lA in terms of the mesh currents
ii) Write the equations for the mesh currents from the current sources
iii) Apply KVL to the loop(s) identified in step i
iv) Write the equation relating the mesh currents using the simplest superloop
✓ Screenshot 202...
=>
Also from mesh 4;
IA = (4
(b) (1) Equations from current Sources:
from 2A current source in mesh 2:
2=-2A
21A-36-12CC-1)-8(c;-(3)=0
23 c; - 1262-8 13 = 21A
(iv) Since there is a current source of 5A
in common branch of mesh 3 and mesh4.
KVL can not be applied to individual
mesh 3 and mesti4.
Forming superloop using mesh 3 and
mesh 4 and applying KVL:
-1063-8 (3-1)-18-514= =0
86-1863-564 = 18
A+ V+
A- V-
-1.586 A
10
247.216 mA
12
2A
5A
-5.247 A
t = 7.635 s
time step 5 us
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,