2. Triple Integral Applications 2a. Find the volume of the solids in the first octant which bounded by xy-plane, yz-plane, plane x+y=4 and z = x²+6. 2b. Given the region bounded in between z = r² and z =1, side by the cylinder r² ≤ 4, and in the first and second octant. Determine its volume by using cylindrical coordinate system. 2c. Solving Using Spherical Coordinates 2c. Calculate the volume of region which is bounded above by sphere of 2 x² + y²+z² = 81 and below by cone z = √x² + y² in the first octant.
2. Triple Integral Applications 2a. Find the volume of the solids in the first octant which bounded by xy-plane, yz-plane, plane x+y=4 and z = x²+6. 2b. Given the region bounded in between z = r² and z =1, side by the cylinder r² ≤ 4, and in the first and second octant. Determine its volume by using cylindrical coordinate system. 2c. Solving Using Spherical Coordinates 2c. Calculate the volume of region which is bounded above by sphere of 2 x² + y²+z² = 81 and below by cone z = √x² + y² in the first octant.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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2. Triple Integral Applications
2a.
First step Darw the volume of the solids in the first octant which bounded by xy-plane, yz-plane, plane
x+y=4 and z. = x2+6.
2b.
First draw the region bounded in between z = p and z=1, side by the cylinder r? ≤ 4, and in the first and second octant. Defermine its volume by using cylindrical coordinate system.
2c. Solving Using Spherical Coordinates
2c.
First draw the volume of region which is bounded above by sphere of
x? + y2 + 2? = 81 and below by cone z = x? + y? in the first octant.
first step drawing second step calculation
i need to cal by hand
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