A sphere of radius r floats in water. The volume of a spherical segment is (3 rh² – h° ). Find the depth to which a sphere of density 800 kg/m² sinks in water as a fraction of its radius (see figure) using the bisection and the false position method. Hint: Use highlighted part as function f (h') Applying Archimede's principle we obtain: 4 (3rk* – k')Puo8 3 which simplifies to 4r'800 = (3rh² – h’)1000=3.2r' = 3rh² – h h →h° – 3h² +3.2 = 0 where h' = -

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Question 2:
A sphere of radius r floats in water. The volume of a spherical segment is (3 rh – h' ). Find the depth to which a
sphere of density 800 kg /m? sinks in water as a fraction of its radius (see figure) using the bisection and the false
position method.
Hint: Use highlighted part as function f (h*)
Applying Archimede's principle we obtain:
4
ar'P phan8 =(3rh – h')Pu08
which simplifies to
4r'800 = (3rh² – h’)1000=3.2r = 3rh² – h’
>h – 3h² +3.2 = 0 where h* = -
Transcribed Image Text:Question 2: A sphere of radius r floats in water. The volume of a spherical segment is (3 rh – h' ). Find the depth to which a sphere of density 800 kg /m? sinks in water as a fraction of its radius (see figure) using the bisection and the false position method. Hint: Use highlighted part as function f (h*) Applying Archimede's principle we obtain: 4 ar'P phan8 =(3rh – h')Pu08 which simplifies to 4r'800 = (3rh² – h’)1000=3.2r = 3rh² – h’ >h – 3h² +3.2 = 0 where h* = -
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