A sphere of radius r floats in water. The volume of a spherical segment is (3 rh² – h° ). Find the depth to which a sphere of density 800 kg/m² sinks in water as a fraction of its radius (see figure) using the bisection and the false position method. Hint: Use highlighted part as function f (h') Applying Archimede's principle we obtain: 4 (3rk* – k')Puo8 3 which simplifies to 4r'800 = (3rh² – h’)1000=3.2r' = 3rh² – h h →h° – 3h² +3.2 = 0 where h' = -
A sphere of radius r floats in water. The volume of a spherical segment is (3 rh² – h° ). Find the depth to which a sphere of density 800 kg/m² sinks in water as a fraction of its radius (see figure) using the bisection and the false position method. Hint: Use highlighted part as function f (h') Applying Archimede's principle we obtain: 4 (3rk* – k')Puo8 3 which simplifies to 4r'800 = (3rh² – h’)1000=3.2r' = 3rh² – h h →h° – 3h² +3.2 = 0 where h' = -
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please help me to find solution by above mention methods
![Question 2:
A sphere of radius r floats in water. The volume of a spherical segment is (3 rh – h' ). Find the depth to which a
sphere of density 800 kg /m? sinks in water as a fraction of its radius (see figure) using the bisection and the false
position method.
Hint: Use highlighted part as function f (h*)
Applying Archimede's principle we obtain:
4
ar'P phan8 =(3rh – h')Pu08
which simplifies to
4r'800 = (3rh² – h’)1000=3.2r = 3rh² – h’
>h – 3h² +3.2 = 0 where h* = -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe07cbeeb-e0c8-44ef-87c5-6a19323f465b%2Fd8b78971-e36f-4609-814e-bf2c124133f6%2Fe0ngnap_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 2:
A sphere of radius r floats in water. The volume of a spherical segment is (3 rh – h' ). Find the depth to which a
sphere of density 800 kg /m? sinks in water as a fraction of its radius (see figure) using the bisection and the false
position method.
Hint: Use highlighted part as function f (h*)
Applying Archimede's principle we obtain:
4
ar'P phan8 =(3rh – h')Pu08
which simplifies to
4r'800 = (3rh² – h’)1000=3.2r = 3rh² – h’
>h – 3h² +3.2 = 0 where h* = -
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