2. Give the pK₂ values for the following compounds and then rank them in terms of increasing acidity. Explain why the values change so dramatically (each pKa unit is an order of magnitude) from one member of the series to the next. NH3 HF CH4 H₂O
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- What is the pKa value of molecule C? OH soni +The Ka value for chlorous acid (HCIO₂) is 1.1 × 10-2, while the Ka for nitrous acid (HNO₂) is 4.6 x 10-4. Calculate the equilibrium constant of the reaction of HCIO₂ with NO₂. Predict whether the reaction equilibrium favors reactants or products. You have calculated the Keq to be equal to 24. Predict whether the reaction equilibrium favors reactants or products. A) Reactants B) Products C) The reaction produces an equal mixture of reactants and products.What steps would you need to take to calculate the pKa1 and pKa2 of something? For example: hydrosulfuric acid H2S(aq) (-38.6 ΔH^0 f kJ mol^-1).
- Rank the following structures in the order of their acidity (1=most acidic, 4=least cidic) SH OH SH F F SH xx FECalculate the pH of a 0.105 M solution of ethylenediamine (H,NCH,CH,NH,). The pKa values for the acidic form of ethylenediamine (H†NCH,CH,NH) are 6.848 (pKa1) and 9.928 (pK22). pH Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H,NCH,CH,NH,] = M [H,NCH,CH,NH; 1 = M [HNCH,CH,NH] = MAt pH=7.79, what is the ratio of H3PO4 to H₂PO4 (pKa=2.1). Show Transcribed Text
- 4. Calculate pH of water solution of Hydrosulphuric acid with concentration of 0,050 M (pKa=6.99)K Calculate the pH of a 0.295 M solution of ethylenediamine (H₂NCH₂CH₂NH₂). The pKa values for the acidic form of ethylenediamine (HFNCH₂CH₂NH3) are 6.848 (pKat) and 9.928 (pK₁2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H₂NCH₂CH₂NH₂] = [H₂NCH₂CH₂NH] = [HNCH₂CH₂NH3] = M M MThe pka's of the the three hydrogens of phosphoric acid are 2.15, 7.2 and 12.3. These numbers tell us that it is much more difficult to remove the second and third hydrogens of phoshoric acid. Why do you think this is so?
- o Calculate the pH of a 0.132 M solution of ethylenediamine (H₂NCH₂CH₂NH₂). The pKa values for the acidic form of ethylenediamine (H₂NCH₂CH₂NH³) are 6.848 (pKal) and 9.928 (pK a2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H₂NCH₂CH₂NH¹] = [H NCH₂CH₂NH₂ ] = M MThe base ephedrine has a pKa value of 9.6. Calculate the theoretical end point pH when a 0.1 M solution of ephedrine is titrated with 0.1 M HCl.If a diprotic acid, H2A, has a pK1 = 2.20 and pK2 = 9.31, what is the principal species of this compound at pH = 5.13? O H2A O A2- OHA O H3A+