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Given the Ka values (in parentheses) for the following acids: HSO4– (Ka= 1.2 x 10–2); HNO2 (Ka= 4.0 x 10–4); HC2H3O2 (Ka= 1.8 x 10–5); Calculate Kc values for the following acid-base equilibria: (a) HSO4–(aq) + C2H3O2–(aq) ⇌ HC2H3O2(aq) + SO42–(aq) (b) HC2H3O2(aq) + NO2–(aq) ⇌ HNO2(aq)+ C2H3O2–(aq)

Given the Ka values (in parentheses) for the following acids: HSO4– (Ka= 1.2 x 10–2); HNO2 (Ka= 4.0 x 10–4); HC2H3O2 (Ka= 1.8 x 10–5); Calculate Kc values for the following acid-base equilibria: (a) HSO4–(aq) + C2H3O2–(aq) ⇌ HC2H3O2(aq) + SO42–(aq) (b) HC2H3O2(aq) + NO2–(aq) ⇌ HNO2(aq)+ C2H3O2–(aq)

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Given the Ka values (in parentheses) for the following acids:

HSO4– (Ka= 1.2 x 10–2); HNO2 (Ka= 4.0 x 10–4); HC2H3O2 (Ka= 1.8 x 10–5);

Calculate Kc values for the following acid-base equilibria:

(a) HSO4–(aq) + C2H3O2–(aq) ⇌ HC2H3O2(aq) + SO42–(aq)

(b) HC2H3O2(aq) + NO2–(aq) ⇌ HNO2(aq)+ C2H3O2–(aq)

Expert Solution
Step 1

Given data,

Ka for HSO4- = 1.2 x 10-2

Ka for HNO2 = 4.0 x 10-4

Ka for HC2H3O2 = 1.8 x 10-5

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