2. A 3-phase, 75 MVA, 11-8 kV star-connected alternator with a solidly earthed neutral point has the fol- lowing p.u. impedances based on rated phase voltage and rated phase current : Positive phase sequence impedance Negative phase sequence impedance Zero phase sequence impedance = j 2 p.u. = j 0.16 p.u. = j 0.08 p.u. Determine the steady-state fault current for the following: (i) 3-phase symmetrical short-circuit (ii) one line-to-earth fault (iii) two line-to-earth fault. The generated e.m.f. per phase is equal to the rated voltage. [(i)1840 A (ii) 4920 A (iii) 3580 A]
2. A 3-phase, 75 MVA, 11-8 kV star-connected alternator with a solidly earthed neutral point has the fol- lowing p.u. impedances based on rated phase voltage and rated phase current : Positive phase sequence impedance Negative phase sequence impedance Zero phase sequence impedance = j 2 p.u. = j 0.16 p.u. = j 0.08 p.u. Determine the steady-state fault current for the following: (i) 3-phase symmetrical short-circuit (ii) one line-to-earth fault (iii) two line-to-earth fault. The generated e.m.f. per phase is equal to the rated voltage. [(i)1840 A (ii) 4920 A (iii) 3580 A]
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.7MCQ
Related questions
Question
![2. A 3-phase, 75 MVA, 11-8 kV star-connected alternator with a solidly earthed neutral point has the fol-
lowing p.u. impedances based on rated phase voltage and rated phase current :
Positive phase sequence impedance
Negative phase sequence impedance
Zero phase sequence impedance
=
j 2 p.u.
=
j 0.16 p.u.
=
j 0.08 p.u.
Determine the steady-state fault current for the following: (i) 3-phase symmetrical short-circuit (ii) one
line-to-earth fault (iii) two line-to-earth fault. The generated e.m.f. per phase is equal to the rated voltage.
[(i)1840 A (ii) 4920 A (iii) 3580 A]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a9f15d5-d506-4cf2-8a51-d6f7ee4f8ce4%2Fede0b9a7-4d9a-42d8-b335-a3436f115d48%2Fdhvraim_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. A 3-phase, 75 MVA, 11-8 kV star-connected alternator with a solidly earthed neutral point has the fol-
lowing p.u. impedances based on rated phase voltage and rated phase current :
Positive phase sequence impedance
Negative phase sequence impedance
Zero phase sequence impedance
=
j 2 p.u.
=
j 0.16 p.u.
=
j 0.08 p.u.
Determine the steady-state fault current for the following: (i) 3-phase symmetrical short-circuit (ii) one
line-to-earth fault (iii) two line-to-earth fault. The generated e.m.f. per phase is equal to the rated voltage.
[(i)1840 A (ii) 4920 A (iii) 3580 A]
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