Using Nodal analysis find currents il, i2,13 andi4.. 15 V. i1 v2 i4 30 w 1 A v3 i2 13 50 40
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- 14 A0-volt forward voltage is applied to a silicon diode in series with a kond of 3 k2. Draw ihe de kud line. What is the slope of the line? Selution The value of voltage Vy across diode is given by Vy v- lR Since R and V are fixed values, this nquation can by represented by a straight line on V-ly characteristics of diode; thn is de kud foe. When I 0, maximum voltage across the diode V 30 V. This is point BC30, 0). 10 mA 30 V Fig. 2.25 Problem 2.4.Derive the current equations for the circuit shown below, using the labels as shown.Note that rz here is a model of the parasitic imperfection of the Zener diode.a) IL = ?b) II = ?c) IZ = ?d) What impact does rz have on VL?Q 2) A single phase half-wave uncontrolled rectifier with RL load is shown With R=1002, La 0. 1H w-377rad/s and V 100V, Determine: a) An expression for the load current i(t). b) The value of the current at t3D16 ms. c) The average load current (1C WLialx197=ア7.9 =121 V, = V, sinfar) 17.2 0.360
- What is ohm's law scvvhhkjbjb14 A 30 volt forward valtuge is applied to a silicon diode in series with a lond of 3 ka. Draw the de kud ine. What is the slope of the line? Solutlon The value of voltage Vy acrass diode is given by V, - V- lR Since R and V are fixal values, this equation can by represented by a straight line on V-ly characteristics of diode; thw is de kuad loe. When I 0, maximum volage across the diode V- 30 V. This is point DC30, 0). 10 mA 30 V Fig. 2.25 Problem 2.4.answer number 2.write your solution pls.
- 24 A 30-volt forward voltage is applied to a silicon diode in series with a kond of 3 k2. Draw the de kud line What is the slope of the line? Solution The value of voltage Vy across diode is given by Vy V-R Since R, and V are fixol values, this equation can by represented by a straight line on V-ly characteristics of diode; ths is de kuad lie. When Iy 0, maximum voltage across the diode V 30 V. This is point B(30, 0). 10 mA 30 V Fig. 2.25 Problem 2.4.I need the answer as soon as possibleReference 7 segment display: Solve for the segments: "d, e, and f." Show your work 1. KMAPs 2. Reduced equation to lite up the segment 3. Describe the operation of Lab 12 4. If you were to add a 4th seven-segment, Describe your design process.
- For the ideal-diode clipper circuit given below, VS = 12.sinwt V. a. Determine the output voltage Vout and sketch this function. b. Remove the short circuit between points x and y, and replace it with a 2k2 Resistor. Find the range of values of VS for; D1 and D2 are OFF D1 is ON and D2 is OFF D1 is OFF and D2 is ON Is it possible for both D1 and D2 to be ON? y 1kO 3V D2 VS 3kQ. Vout D1 6Vb) Use the ALU 74181 in the figure below and the tables (one is enough; second maybe, need to check the new kit) to implement : A + B, A – B, A. B. (MSB) (LSB) 10 (MSB) F3 F2 F1 FO S3 Cn+4 16 s2 20 U14 15 S1 14 so A3 A2 A1 AO B3 B2 B1 B0 M Cn 24 23 22 21 28 27 T26 25 (LSB) (MSB) (LSB)(MSB) (LSB) And given that under M = 1 the circuit performs the following arithmetic and logic functions according to Table 11.1. Input selection S3 Output M-H S2 SI Cn=L. F3 F2 F1 FO A 1 -A В -B A&B AxB 1 A'B 1 Ax(-B) (-A)xB (-A)x(-B) 1 1 ACTIVE HIGH DATA M-L: ARITHMETIC OPERATIONS SELECTION M-H LOGIC s3 s2 s1 so Ino carry) (with carry) F-A PLUS 1 F- LA + B) PLUS 1 F- (A + BI PLUS 1 FUNCTIONS L L F-A F-A+B F-AB F-A H FA+B F-A+T F- MINUS 1 12s COMPL) F-A PLUS AB F- IA + BI PLUS AB L L L L F-0 F-ZERO F- AB F-A PLUS AB PLUS 1 F- (A + BI PLUS AB PLUS 1 L L L H L F-AOB F- AB L L F-A MINUS B MINUS 1 F-A MINUS B F- AB MINUS 1 F- A F-A PLUS AB PLUS1 F-A PLUS B PLUS 1 F- IA + B PLUS AB PLUS 1 L H L F-A PLUS AB…24 A M0-volt forwurd voltage is applied to a silicon diode in series with a load of 3 k2. Draw the de kud line. What is the slope of the line? Solution The value of voltage Vy across diode is given by Vy V-R Since R and V are fixod values, this equation can by represented by a straight line on V-ly characteristics of diode; the is de kud li. When lg 0, maximum voltage across the diode V 30 V. This is point B(30, 0). 10 mA 30 V Fig. 2.25 Problem 2.4.