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- Histamine binds to the H1 G-protein-linked receptor to initiate the itchiness and airway constriction associated with an allergic response. If a mutation in the associated G-protein’s alpha subunit prevented the hydrolysis of GTP how would the allergic response change? More severe allergic response compared to normal G-protein signaling. Less severe allergic response compared to normal G-protein signaling. No allergic response. No change compared to normal G-protein signaling.= 20 nM. The rate of receptor-ligand complex formation with an A receptor-ligand complex has a dissociation constant of Ka added ligand concentration of 10 µM is 5 × 10³ s¯¹. What is the value of the reverse rate constant, k_₁ ? k_₁ = 8-1true or false 6. Nucleotides are more acidic than nucleosides and nitrogenous bases.7. Similar to aromatic amino acids, the sugar-phosphate backbone also absorbs a wavelength of 260 to 280 nm.8. Cyclic adenosine monophosphate relays the primary signal to the target mechanism inside the cell.9. Adenine has higher UV absorbing capacity compared to thymine.10. Adenine and guanine are more soluble in aqueous solutions compared to adenosine and guanosine
- Need help Intaractions of FAK kinase which directly depend on the tyrosine residue 397 (Y397) are inhibbited by a chemical compound in cancercells. Intaraction of FAK kinase with what proteins are blocked by this inhibition? (please give a listt of them all, and that's it). Studies on CAMP actions in cultured cells usually involve adding to the cell culture not CAMP, but dibutyryl CAMP (see structure). Why is this structural modification necessary? How could you test the premise that di-Bu-CAMP has the same biochemical effects as CAMP? N. N= Nat Dibutyryl CAMP O3 of 16 Which statement about the IP3 DAG pathway is false? O Diacylglycerol can act as a second messenger. Inositol trisphosphate can act as a second messenger. O Protein kinase C can phosphorylate a wide variety of proteins. O Inositol trisphosphate remains bound to the membrane after phospholipase C catalyzes its formation. Inositol trisphosphate can open ion channels in the membraņes of smooth endoplasmic reticulum, releasing calcium into the cytoplasm.
- Calmodulin dependent kinase 1 protein contains 14 tyrosine's 4 tryptophans and 6 phenylalanines the molar extinction coefficient of this protein is approximately 39,200 abs m^-1 cm^-1 not enough information 11,200 abs m^-1 cm^-1 83,200 abs m^-1 cm^-18 80 wh 가 Vt WI V N Messenger GDP 1 BY G protein Receptor Lumen of endoplasmic reticulum Ca Membrane of endoplasmic reticulum 2 " GDP GTP GTP (5b) Phospholipase C PIP 2 3 IP3 DAG (6c) Calmodulin Protein kinase Protein-P © 2011 Pearson Education, Inc. (4a) 6b Protein kinase C ATP + protein Extracellular fluid (5a) Response in cell (contraction, metabolism, transport) ADP protein- p (6a) Response in cell Response in cell (contraction, secretion) Cytosol Which Ga protein activates phospholipase C? Which secondary messenger opens the ligand gated ion channel? What does a kinase do? What does a phosphatase do?BONUS QUESTION! In neurons, the proteolytic enzyme y-secretase produces the Aß amyloid peptides shown below. The AB40 peptide is thought to play a protective role in the neuron. However, the AB42 peptide appears to be toxic since it is found in the amyloid plaques that cause Alzheimer's Disease (AD). AB40 and AB42 are identical, except that AB42 contains two extra amino acid residues (shown in red) at the C-terminal end. Based on your knowledge of amino acids and proteins, which of the following factors is most likely to explain the greater plaque-forming activity of AB42 compared to AB40? Sequence of Aß40: DAEFRHDSGYEVHHQKLVFFAEDVGSNKGAIIGLMVGGVV Sequence of AB42: DAEFRHDSGYEVHHQKLVFFAEDVGSNKGAIIGLMVGGVVIA O The greater length of AB42 makes it more likely to aggregate and form plaques. O AB42 has a lower pl than AB40, which makes it more likely to aggregate at physiological pH. O AB42 is more hydrophobic than AB40, which makes it harder to clear from the cell and thus more likely to…
- Pls send solution fast within 10 minutes and i will give like for sure Solution must be in typed form Calcium ions bind to the SERCA Ca2+ -ATPase, which has two identical calcium sites, in two stages with apparent equilibrium constants K1=7×105M−1 and K2=2×106M−1 . a.) Calculate K. Note: K is not 0.1*1013 or 14*1011 or 1*1012. b.) Calculate τ.added ligand concentration of 10 µM is 5 × 10³ s¹. What is the value of the reverse rate constant k_1 = 1 ×10-4 Incorrect Macmillan Learning You have not correctly calculated the value of the reverse rate constant. To begin, calculate the value of k₁ by dividing the rate of receptor-ligand complex formation (the rate of the forward reaction) by the ligand concentration. k₁ = rate forward [L] Then, calculate the value of the reverse rate constant, k_₁, by multiplying the dissociation constant, Kd, and the forward rate constant, k₁. k_1 = Kak₁During an SAR effort to identify tyrosine kinase inhibitors, it was found that compound 2 was significantly more potent and selective than compound 1. To what might you attribute this improvement in activity and selectivity? Explain. IC-5 micromolar IC-0.1 mromolar
