16. Horizontal members B and C in the Fig. P1-3 may be considered rigid and of negligible weight. Pins 1 and 2 are smooth. Wires D and F are vertical. The allowable tensile stress for wire D is 0.833 GPa and that for wire F is 0.555 GPa. What maximum value may P have? Wire D is 30 cm long and wire F is 60 cm long. The materials have the same E = 1.67 x 10¹¹ N/m². If the rigid bars are horizontal before P is applied, what is the angle between them when P is 1 kN. ON B (rigid) -1.2 m- 0.3 m F (2 mm diameter) D (1.5 mm diameter) to +00m-p 0.6 m- Fig. P1-3 P 0.9 m C (rigid) wwwwww [Ans. 1.26 kN, 2.12°]

16. Horizontal members B and C in the Fig. P1-3 may be considered rigid and of negligible weight. Pins 1 and 2 are smooth. Wires D and F are vertical. The allowable tensile stress for wire D is 0.833 GPa and that for wire F is 0.555 GPa. What maximum value may P have? Wire D is 30 cm long and wire F is 60 cm long. The materials have the same E = 1.67 x 10¹¹ N/m². If the rigid bars are horizontal before P is applied, what is the angle between them when P is 1 kN. ON B (rigid) -1.2 m- 0.3 m F (2 mm diameter) D (1.5 mm diameter) to +00m-p 0.6 m- Fig. P1-3 P 0.9 m C (rigid) wwwwww [Ans. 1.26 kN, 2.12°]

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

400mm Find the required spacing of intermediate stiffeners if V*=1600KN 25mm • Check the adequacy of a pair of stiffeners 90mmx12mm • Check the web crushing capacity if the reaction of 1600kN is applied over a stiff bearing length of 250mm at the end of the beam (note that the spread of stress can only go in one direction) • Homework extension: Check the adequacy of an endplate stiffener 300 wide by 16mm thick 12mm Use Grade 300 Steel 1440mm
Problem 2 The rigid bar is plnned at A and held by two flexible bars at E and C. The load P Is applled at B. The two flexible bars FE and DC each have a diameter of 1 In. The flexible bars are elastic- perfectly plastic with a yleld stress equal to 20 ksl and a yleld strain of 0.001. Determine the following: The load R, at first yleld and the corresponding deflection at B, &, The ultimate load Pu and the corresponding deflection du The permanent deflection and residual stresses in each rod if the ultimate load is removed Construct P - A curve showing yield, ultimate and permanent deformation o (ksi) 1 ft E F 1 ft1 ft 20 B P e (in./in.) 0.001 1 ft D 2 ft 1 ft A
A 5.2-m-long aluminum tube (1) is to be connected to a 2.2-m-long bronze pipe (2) at B. When put in place, however, a gap of 9 mm exists between the two members, as shown. Aluminum tube (1) has an elastic modulus of 69 GPa and a cross-sectional area of 1980 mm2. Bronze pipe (2) has an elastic modulus of 93 GPa and a cross-sectional area of 3970 mm2. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine: (a) the normal stresses ?1, ?2 produced in each of the members. (b) the displacement (change in length of material (2), up is positive) uB of flange B with respect to support A. 5.2 m 2.2 m Answers: (a) 0₁ = (b) Ug = C (1) B (2) -95.40 1.126 9 mm MPa, 0₂ = mm. -47.58 MPa
A rigid bar ABCD is supported by two bars as shown in the figure. There is no strain in the vertical bars before load P is applied. After load P is applied, the normal strain in rod (1) is -1350 µm/m. Determine the normal strain in rod (2) if there is a 1-mm gap in the connection at pin C before the load is applied. A 240 mm B (1) O 1281 um/m O 1877 µm/m O 1141 µm/m O 1358 µm/m O 999 µm/m 360 mm (2) Rigid bar 900 mm C 140 mm, 1,500 mm
The rigid bar ABCD supports point loads at A and D and is being supported by two bars at B and C. Determine the absolute value of the deformation at point C. (in mm) 120KN 4m Sm A B L= 6m 9o kN L-4m A= 0.04 m A = 0.0 6m² E=200 GAa E=80 GPa
Compound axial member ABC has a uniform diameter of d = 1.25 in. • Segment (1) is an aluminum [E1 = 10000 ksi] alloy. The length of segment (1) is L1 = 100 in. • Segment (2) is a copper [E2 = 17000 ksi] alloy. The length of segment (2) is L2 = 140 in. When axial force Pis applied, a strain gage attached to copper segment (2) measures a normal strain of ɛ2 = 2300 uin./in. in the longitudinal direction. What is the total elongation of member ABC? L2 (1) Aluminum B (2) Copper Answer: in, AL = i
3) The rigid link is supported by steel wire (1) with an unstretched length of 200 mm and cross-sectional area of 22.5 mm?. Member (2) is a short aluminum of initial length 50 mm and cross-sectional area of 40 mm?. The modulus of elasticity of the steel wire is 200 GPa and the aluminum block is 70 GPa. a) Draw the deflected shape of the rigid member and clearly label the deformation of members (1) and (2). b) Write the equilibrium and compatibility equations needed to solve the problem along with the supporting sketches. Hint: Be sure to carefully consider if the members are elongating or shortening; this must be represented mathematically. c) Calculate the internal forces in both axial members and clearly indicate tension or compression. [Ans. to Check: F2 = 535 N]
Qn 2, Part 1 only
The steel bars are firmly attached to rigid supports. Initially the temperature is 840F. Determine the stress in bars AC and CB when the temperature becomes -600F. Use E = 29 x 106 psi and α = 6.50 x 10-6/ 0F.