A 5.2-m-long aluminum tube (1) is to be connected to a 2.2-m-long bronze pipe (2) at B. When put in place, however, a gap of 9 mm exists between the two members, as shown. Aluminum tube (1) has an elasti modulus of 69 GPa and a cross-sectional area of 1980 mm2. Bronze pipe (2) has an elastic modulus of 93 GPa and a cross-sectional area of 3970 mm2. If

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter6: Introduction To Mechanical Properties
Section: Chapter Questions
Problem 6.3P: Compare the engineering and true secant elastic moduli for the natural rubber in Example Problem 6.2...
Question
A 5.2-m-long aluminum tube (1) is to be connected to
a 2.2-m-long bronze pipe (2) at B. When put in place,
however, a gap of 9 mm exists between the two
members, as shown. Aluminum tube (1) has an elastic
modulus of 69 GPa and a cross-sectional area of
1980 mm2. Bronze pipe (2) has an elastic modulus of
93 GPa and a cross-sectional area of 3970 mm2. If
bolts are inserted in the flanges and tightened so that
the gap at B is closed, determine:
(a) the normal stresses ?1, ?2 produced in each of the
members.
(b) the displacement (change in length of material (2),
up is positive) uB of flange B with respect to support
A.
5.2 m
2.2 m
Answers:
(a) 0₁ =
(b) Ug =
C
(1)
B
(2)
-95.40
1.126
9 mm
MPa, 0₂ =
mm.
-47.58
MPa
Transcribed Image Text:A 5.2-m-long aluminum tube (1) is to be connected to a 2.2-m-long bronze pipe (2) at B. When put in place, however, a gap of 9 mm exists between the two members, as shown. Aluminum tube (1) has an elastic modulus of 69 GPa and a cross-sectional area of 1980 mm2. Bronze pipe (2) has an elastic modulus of 93 GPa and a cross-sectional area of 3970 mm2. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine: (a) the normal stresses ?1, ?2 produced in each of the members. (b) the displacement (change in length of material (2), up is positive) uB of flange B with respect to support A. 5.2 m 2.2 m Answers: (a) 0₁ = (b) Ug = C (1) B (2) -95.40 1.126 9 mm MPa, 0₂ = mm. -47.58 MPa
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