13. In humans, red-green color blindness is recessive to normal sight. The gene for this trait is carried on the X chromosome (remember, Y is genetically inert). In each of the following, give all types of offspring and their expected ratios: Tanvry (a) a colorblind man married to a heterozygous normal-sighted woman; (b) a color-blind man married to a homozygous normal-sighted woman; (c) a normal man married to a woman heterozygous for color blindness; pob (d) a normal man married to a color-blind woman. (8

13. In humans, red-green color blindness is recessive to normal sight. The gene for this trait is carried on the X chromosome (remember, Y is genetically inert). In each of the following, give all types of offspring and their expected ratios: Tanvry (a) a colorblind man married to a heterozygous normal-sighted woman; (b) a color-blind man married to a homozygous normal-sighted woman; (c) a normal man married to a woman heterozygous for color blindness; pob (d) a normal man married to a color-blind woman. (8

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Description: 13. In humans, red-green color blindness is recessive to normal sight. The gene for this traitis carried on the X chromosome (remember, Y is genetically inert). In each of the dfollowing, give all types of offspring and their expected ratios:2917039

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)

10th Edition

ISBN:9781305967359

Author:STARR

Publisher:STARR

Chapter14: Human Inheritance

Section: Chapter Questions

Problem 2GP: Human females have two X chromosomes XX; males have one X and one Y chromosome XY. a. With respect...

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Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele?
Human females have two X chromosomes XX; males have one X and one Y chromosome XY. a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. A female homozygous for an X-linked allele can produce how many types of gametes with respect to that allele? c. A female heterozygous for an X-linked allele can produce how many types of gametes with respect to that allele?
Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?
7) In cats, the gene for coat color is both X-linked and incompletely dominant. There are black coat and yellow coat alleles, with calico (tortoise shell) as the heterozygous form. If a yellow male mates with a calico female, what are the expected offspring phenotypes (in percent)? hbit
1) Perception of a bitter taste from phenylthiocarbamide (PTC) is dominant (T) to not being able to taste PTC. Albinism is recessive to normal pigmentation (A). The genes controlling these traits are on separate chromosomes. a. A normally pigmented woman who cannot taste PTC has a father who is an albino taster, marries a many homozygous for normal pigmentation who is a PTC taster, but whose mother did not taste PTC. What are the genotypes of the woman and man listed here? b. Assuming the man and woman in the above section have children, what percentage of these children will be albino? c. What percentage of these children will have the same phenotype as their mother?
8. The autosomal (not X-linked) gene for brachydactyly, short fingers, is dominant to normal finger length. Assume that a female with brachydactyly in the heterozygous condition is married to a man with normal fingers. What is the probability that(a) their first child will have brachydactyly?(b) their first two children will have brachydactyly?(c) their first child will be a brachydactylous girl?
.Certain forms of human color blindness are inherited as X-linkedrecessive traits. Hemizygous males are color-blind, but heterozygous females are not. However, heterozygous females sometimeshave partial color blindness.A. Discuss why heterozygous females may have partial color blindness.B. Doctors identified an unusual case in which a heterozygousfemale was color-blind in her right eye but had normal colorvision in her left eye. Explain how this might have occurred.
7. Hereditary ichthyosis in humans is a sex-linked trait. If a normal male and a carrier female produce offspring, what will be the phenotypic ratios of: Normal females to scaly females? Normal males to scaly males? 8. Raedwald is color blind. His four sisters and his parents all have normal color vision. Who passed this condition on to Raedwald, and what can be said for certain about the genotypes of his maternal and paternal grandparents? wwwwM
9. Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
6. An X-linked ichthyosis is a recessive form of a family of skin diseases caused by a hereditary deficiency of the steroid sulfatase (STS) enzyme. A woman heterozygous for this mutation mates with the phenotypically normal man and produces an XXY son who suffers from the disorder. Which of the answer choices can explain this result? Briefly justify your answer. A) nondisjunction in meiosis I in the father B) nondisjunction in meiosis I in the mother C) nondisjunction in meiosis II in the father D) nondisjunction in meiosis II in the mother
5) Humans who have an abnormally high level of cholesterol are said to suffer from familialhypercholesterolemia.  The gene for this disorder is dominant (C). A man who isheterozygous for familial hypercholesterolemia marries a woman who is homozygousfor the recessive allele. What is the probability that they will have children that sufferfrom this disorder? please draw the puutnet square and also write the parents and gemtaics top the puutnet square thanks
14. ii) If Individuals #6 and #7 have another daughter what are the chances that she will be affected. 1 II IV a) The pedigree above shows the passing on of colorblindness. What sex is MOST likely to be carriers of colorblindness? b) Why does individual IV-7 (a female) have colorblindness? c) Why do all the daughters in generation II carry the colorblind gene? d) List two h generation colorblind males. 15. Explain sex linked inheritance with examples. 16. Explain what happens during these following sicknesses and why it happens? i) Sickle cell anemia i Hemophilia 17. What do you understand by the term "Multiple Alleles"? Define the followings: Trait true breeding cross P generation F1 generation monohybrid cross F2 generation dominant recessive law of segregation genotype phenotype homozygous heterozygous test cross dihybrid cross law of independent assortment pedigree autosomal recessive Punnett square autosomal inheritance autosomal dominant