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12. Calculate E° cell for a silver-aluminum cell in which the cell reaction is Al(s)+3Ag+(aq) → Al3+(aq) + 3Ag(s) (1) Al3+(aq) +3e → Al(s) E° = -1.66 V (2) Al(OH)4(aq) + 3e → Al(s) + 40H(aq) E° = -2.35 V (3) Ag (aq) + e→ Ag(s) E° = +0.80 V (4) Ag2+(aq) + e → Ag+(aq) E° = +2.00 V A. -2.46 V B. +0.86 V C. -0.86 V D. +2.46 V E. None of these Give clear solution

12. Calculate E° cell for a silver-aluminum cell in which the cell reaction is Al(s)+3Ag+(aq) → Al3+(aq) + 3Ag(s) (1) Al3+(aq) +3e → Al(s) E° = -1.66 V (2) Al(OH)4(aq) + 3e → Al(s) + 40H(aq) E° = -2.35 V (3) Ag (aq) + e→ Ag(s) E° = +0.80 V (4) Ag2+(aq) + e → Ag+(aq) E° = +2.00 V A. -2.46 V B. +0.86 V C. -0.86 V D. +2.46 V E. None of these Give clear solution

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section: Chapter Questions
Problem 94GQ: A voltaic cell is constructed in which one half-cell consists of a silver wire in an aqueous...
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12. Calculate E° cell for a silver-aluminum cell in which the cell reaction is Al(s)+3Ag+(aq) → Al3+(aq) + 3Ag(s) (1) Al3+(aq) +3e → Al(s) E° = -1.66 V (2) Al(OH)4(aq) + 3e → Al(s) + 40H(aq) E° = -2.35 V (3) Ag (aq) + e→ Ag(s) E° = +0.80 V (4) Ag2+(aq) + e → Ag+(aq) E° = +2.00 V A. -2.46 V B. +0.86 V C. -0.86 V D. +2.46 V E. None of these Give clear solution
Transcribed Image Text:12. Calculate E° cell for a silver-aluminum cell in which the cell reaction is Al(s)+3Ag+(aq) → Al3+(aq) + 3Ag(s) (1) Al3+(aq) +3e → Al(s) E° = -1.66 V (2) Al(OH)4(aq) + 3e → Al(s) + 40H(aq) E° = -2.35 V (3) Ag (aq) + e→ Ag(s) E° = +0.80 V (4) Ag2+(aq) + e → Ag+(aq) E° = +2.00 V A. -2.46 V B. +0.86 V C. -0.86 V D. +2.46 V E. None of these Give clear solution
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