4. The solution of the HMOs for the allyl cation gives the following in order of increasing electronic energy: H₂C + CH2 ¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03 ¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3 = - Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03 Given these solutions, draw the three MOs with the correct phases and relative sizes. (10 points)
4. The solution of the HMOs for the allyl cation gives the following in order of increasing electronic energy: H₂C + CH2 ¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03 ¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3 = - Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03 Given these solutions, draw the three MOs with the correct phases and relative sizes. (10 points)
Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter5: Alkenes: Bonding, Nomenclature, And Properties
Section: Chapter Questions
Problem 5.31P
Related questions
Question
![4. The solution of the HMOs for the allyl cation gives the following in order of
increasing electronic energy:
H₂C
+
CH2
¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03
¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3
=
-
Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03
Given these solutions, draw the three MOs with the correct phases and relative
sizes. (10 points)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5dd7fe98-037c-42cd-9ead-306bf9f2226e%2Fb967e2ee-23df-42a8-bc0c-bc381d822147%2Fp5hcrmk_processed.png&w=3840&q=75)
Transcribed Image Text:4. The solution of the HMOs for the allyl cation gives the following in order of
increasing electronic energy:
H₂C
+
CH2
¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03
¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3
=
-
Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03
Given these solutions, draw the three MOs with the correct phases and relative
sizes. (10 points)
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