4. The solution of the HMOs for the allyl cation gives the following in order of increasing electronic energy: H₂C + CH2 ¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03 ¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3 = - Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03 Given these solutions, draw the three MOs with the correct phases and relative sizes. (10 points)
4. The solution of the HMOs for the allyl cation gives the following in order of increasing electronic energy: H₂C + CH2 ¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03 ¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3 = - Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03 Given these solutions, draw the three MOs with the correct phases and relative sizes. (10 points)
Chapter5: Stereochemistry At Tetrahedral Centers
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![4. The solution of the HMOs for the allyl cation gives the following in order of
increasing electronic energy:
H₂C
+
CH2
¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03
¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3
=
-
Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03
Given these solutions, draw the three MOs with the correct phases and relative
sizes. (10 points)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5dd7fe98-037c-42cd-9ead-306bf9f2226e%2Fb967e2ee-23df-42a8-bc0c-bc381d822147%2Fp5hcrmk_processed.png&w=3840&q=75)
Transcribed Image Text:4. The solution of the HMOs for the allyl cation gives the following in order of
increasing electronic energy:
H₂C
+
CH2
¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03
¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3
=
-
Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03
Given these solutions, draw the three MOs with the correct phases and relative
sizes. (10 points)
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