PQ-23. At 298 K, the equilibrium constant for this reaction H2(g) + O2(g)= H₂O(l) AG° (kJ mol¹) -237 -229 H₂O(1) H₂O(g) (A) has a value of 1.0 at equilibrium. (B) is larger than the Keq for H2(g) + O2(g)=H₂O(g). (C) cannot be computed since data on O2 and H2 are not provided. (D) will have the same value as the Keq for H2(g) + O2(g)= H₂O(g)
PQ-23. At 298 K, the equilibrium constant for this reaction H2(g) + O2(g)= H₂O(l) AG° (kJ mol¹) -237 -229 H₂O(1) H₂O(g) (A) has a value of 1.0 at equilibrium. (B) is larger than the Keq for H2(g) + O2(g)=H₂O(g). (C) cannot be computed since data on O2 and H2 are not provided. (D) will have the same value as the Keq for H2(g) + O2(g)= H₂O(g)
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 60QAP
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
Transcribed Image Text:PQ-23. At 298 K, the equilibrium constant for this reaction
H2(g) + O2(g)= H₂O(l)
AG° (kJ mol¹)
-237
-229
H₂O(1)
H₂O(g)
(A) has a value of 1.0 at equilibrium.
(B) is larger than the Keq for H2(g) + O2(g)=H₂O(g).
(C) cannot be computed since data on O2 and H2 are not provided.
(D) will have the same value as the Keq for H2(g) + O2(g)= H₂O(g)
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