Suppose you sample 100 times at random with replacement from a population in which 26% of the individuals are successes 1.3. Complete the cell with an expression that evaluates to the chance that the number of successes in the sample is in the interval 26 ± 10 (inclusive on both sides). In other words,determine P(16 ≤X ≤ 36). Hint: You might want to apply your Python indexing knowledge here.

Given: Sample size n=100 Probability of success p=0.26

Answered: 1.3. Complete the cell with an…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Now suppose you are an auditor for a very large corporation. The revenue report involves millions of numbers in a large computer file. Let us say you took a random sample of n = 223 numerical entries from the file and r = 48 of the entries had a first nonzero digit of 1. Let p represent the population proportion of all numbers in the corporate file that have a first nonzero digit of 1.(i) Test the claim that p is less than 0.301. Use ? = 0.05. (a) What is the level of significance?State the null and alternate hypotheses. H0: p < 0.301; H1: p = 0.301H0: p = 0.301; H1: p > 0.301 H0: p = 0.301; H1: p < 0.301H0: p = 0.301; H1: p ≠ 0.301 (b) What sampling distribution will you use? The standard normal, since np > 5 and nq > 5. The standard normal, since np < 5 and nq <…
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Example 17: In a sample of 1000 citizens of India, 540 are wheat eaters and the rest are rice eaters. Can we assume that both rice and wheat are equally popular in India at a%. level of significance?
How many subjects in the "patch only" group would you expect not to quit
2. In a population it is estimated that 20% have a desired trait of interest for the researcher. The researcher wants to know how many people on average he has to draw from a population to get 2 people with the trait. Use rows 20-24 of the Random Number Table to carry out the simulation. Explain clearly how you set up the problem and report your findings. Answer:
A lawn mower company will produce 1,500 lawn mowers by 2020. In an effort to determine how much maintenance-free consumers will buy when they buy lawn mowers, the company decided to conduct a study over the past 1 year of these mowers. First, a random sample was taken by contacting 200 grass mowers. The company owner provides an 800 number and is asked to contact the company when the first repair is needed for the lawn mower. Owners who no longer use lawn mowers to cut their grass are either disqualified or not sampled. After 1 year, it turned out that 187 owners had reported for the first repair. However, the other 74 disqualified themselves. The average number per year until the first improvement was 5.3 times for samples deemed feasible. It is believed that the standard deviation is 1.28 per year. If the company wants to advertise the lawnmower and with a confidence level of 95%, what is the estimated annual mean value of repair-free lawn mower for this lawn mower? What is the…
A pair of dice is rolled 210 times. What is the probability that a total of 7 occurs (a) at least 24 times? (b) between 38 and 48 times inclusive? (c) exactly 35 times? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.
Determine whether the results appear to have statistical significance, and also determine whether the results appear to have practical significance. In a study of a birth sex selection method used to increase the likelihood of a baby being born female, 2031 users of the method gave birth to 995 males and 1036 females. There is about a 19% chance of getting that many babies born female if the method had no effect. Because there is a 19% chance of getting that many babies born female the method had no effect, the method couples would likely use a procedure that raises the likelihood of a baby born female from the approximately 50% rate expected by chance to the % produced by this method. (Round to the nearest integer as needed.) So, this method
A local school board wants to estimate the difference in the proportion of households with school-aged children that would support starting the school year a week earlier, and the proportion of households without school-aged children that would support starting the school year a week earlier. They survey a random sample of 40 households with school-aged children about whether they would support starting the school year a week earlier, and 30 households respond yes. They survey a random sample of 45 households that do not have school-aged children, and 25 respond yes. Assuming the conditions for inference have been met, what is the 90% confidence interval for the difference in proportions of households that would support starting the school year a week earlier? Find the z-table here. 0.75(1-0.75), 0.56(1-0.56) O (0.75 - 0.56) ±1.65 45 40 0.75(1-0.75) 0.56(1-0.56) O (0.75 - 0.56) ±1.96, 85 85 O (0.75 - 0.56) ±1.65, 0.75(1-0.75) 0.56(1-0.56) + 40 45 O (0.75 - 0.56) ±1.96 0.75(1-0.75)…
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1.3. Complete the cell with an expression that evaluates to the chance that the number of successes in the sample is in the interval + 10 (inclusive on both sides). In other words, determine 2016 & X36) Hint: You might want to apply your Python indeving knowledge here