1. What is the equilibrium constant for the following reaction at 25 "C? Ni (s) + Cd²+ (aq) Ni²+ (aq) + Cd (s) E' cell--0.15 V A) 2.1 x 10-12 B) 8.4 x 10-6 C) 1.0 x 10-1 D) 1.2 x 10¹ E) 1.2 x 105 " E=EC-RT Cell- E° -0.0592 -InQ nf E-0.0592 -0.0592 loga = Eº-RTINQ n E-E° + 0.0592 - = 109 Q 0176 1-RT In Q nF log @
1. What is the equilibrium constant for the following reaction at 25 "C? Ni (s) + Cd²+ (aq) Ni²+ (aq) + Cd (s) E' cell--0.15 V A) 2.1 x 10-12 B) 8.4 x 10-6 C) 1.0 x 10-1 D) 1.2 x 10¹ E) 1.2 x 105 " E=EC-RT Cell- E° -0.0592 -InQ nf E-0.0592 -0.0592 loga = Eº-RTINQ n E-E° + 0.0592 - = 109 Q 0176 1-RT In Q nF log @
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Equilibrium
COH= 10-PH
3)PH +POH = 10
POH = -log [OH7
PH+ Por
PK
1. What is the equilibrium constant for the following reaction at 25 "C?
Ni (s) + Cd2+ (aq) → Ni²+ (aq) + Cd (s)
E' cell-0.15 V
I
A) 2.1 x 10-12
B) 8.4 x 10-6
C) 1.0 x 10-1
D) 1.2 x 10¹
E) 1.2 x 105
A) x
E=EC-RT
Eº
-0.0592
I InQ
nf
E-E° + 0.0592
COB) y ₂0 (1)+2 C)x+y
(A) 100 g H₂O (s) at -10 °C
100 g H₂O (liquid) at 0 °C
100 g H₂O (liquid) at 75 °C
100 g H₂O (g) at 110 °C
E) 100 g H₂O (s) at 0 °℃otential
loga = E-RT IN Q
n
= 109 Q
0,176 = log
2. Which quantity in the energy profile below corresponds to the activation energy for
the reverse reaction?
A
Reaction pathway
E-0.0592
n
D) x-y
RT INQ
In
nF
E) y-x
3. Which one of the following will exhibit NO CHANGE in temperature when a small
quantity of heat (e.g., 25 J) is removed from the system? No calculation required.
q) + 2 OH (aq)
4. A 2.00 L flask is filled with 1.5 mol SO3, 2.5 mol SO2, and 0.5 mol O2, and allowed
to reach equilibrium according to the following reaction:
1,5
2.5
0.5
2 SO3 (g) 2 SO2 (g) + O₂ (g)
Kc = 1.0
What will happen to the concentration of oxygen as equilibrium is being achieved?
A. [0₂] will increase.
B. [0₂] will decrease.
C. [0₂] will remain the same.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa02a222c-09b7-48e2-8f10-299d6aeba7af%2F82f4be36-a4e3-4cf5-bbfe-ebe92fec7ced%2Fjd5p2m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Equilibrium
COH= 10-PH
3)PH +POH = 10
POH = -log [OH7
PH+ Por
PK
1. What is the equilibrium constant for the following reaction at 25 "C?
Ni (s) + Cd2+ (aq) → Ni²+ (aq) + Cd (s)
E' cell-0.15 V
I
A) 2.1 x 10-12
B) 8.4 x 10-6
C) 1.0 x 10-1
D) 1.2 x 10¹
E) 1.2 x 105
A) x
E=EC-RT
Eº
-0.0592
I InQ
nf
E-E° + 0.0592
COB) y ₂0 (1)+2 C)x+y
(A) 100 g H₂O (s) at -10 °C
100 g H₂O (liquid) at 0 °C
100 g H₂O (liquid) at 75 °C
100 g H₂O (g) at 110 °C
E) 100 g H₂O (s) at 0 °℃otential
loga = E-RT IN Q
n
= 109 Q
0,176 = log
2. Which quantity in the energy profile below corresponds to the activation energy for
the reverse reaction?
A
Reaction pathway
E-0.0592
n
D) x-y
RT INQ
In
nF
E) y-x
3. Which one of the following will exhibit NO CHANGE in temperature when a small
quantity of heat (e.g., 25 J) is removed from the system? No calculation required.
q) + 2 OH (aq)
4. A 2.00 L flask is filled with 1.5 mol SO3, 2.5 mol SO2, and 0.5 mol O2, and allowed
to reach equilibrium according to the following reaction:
1,5
2.5
0.5
2 SO3 (g) 2 SO2 (g) + O₂ (g)
Kc = 1.0
What will happen to the concentration of oxygen as equilibrium is being achieved?
A. [0₂] will increase.
B. [0₂] will decrease.
C. [0₂] will remain the same.
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