2- Calculate E° cell for the following electrochemical cell: Ni(s) | Ni2*(aq) || Hg2*(aq) | Hg(I) E° cathode = 0.79 V %3D

Chemistry
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Chapter1: Chemical Foundations
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**Problem 2: Electrochemical Cell Calculation**

Calculate \( E^\circ_{\text{cell}} \) for the following electrochemical cell:

\[ \text{Ni(s)} | \text{Ni}^{2+} (\text{aq}) || \text{Hg}_2^{2+} (\text{aq}) | \text{Hg(l)} \]

Given:
- \( E^\circ_{\text{cathode}} = 0.79 \, \text{V} \)

**Explanation:**

This problem involves calculating the standard cell potential (\( E^\circ_{\text{cell}} \)) for a given electrochemical cell. The cell notation represents a galvanic cell with nickel metal and a mercury-based electrolyte. The reduction potential for the cathode (mercury half-cell) is given as 0.79 volts.
Transcribed Image Text:**Problem 2: Electrochemical Cell Calculation** Calculate \( E^\circ_{\text{cell}} \) for the following electrochemical cell: \[ \text{Ni(s)} | \text{Ni}^{2+} (\text{aq}) || \text{Hg}_2^{2+} (\text{aq}) | \text{Hg(l)} \] Given: - \( E^\circ_{\text{cathode}} = 0.79 \, \text{V} \) **Explanation:** This problem involves calculating the standard cell potential (\( E^\circ_{\text{cell}} \)) for a given electrochemical cell. The cell notation represents a galvanic cell with nickel metal and a mercury-based electrolyte. The reduction potential for the cathode (mercury half-cell) is given as 0.79 volts.
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