At 298 K, what is E (in V) for the electrochemical cell below when [Cd^2+ ]=4.700N and [Cu^2+ ]=0.004M

Chemistry
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Chapter1: Chemical Foundations
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At 298 K, what is E (in V) for the electrochemical cell below when [Cd^2+ ]=4.700N and [Cu^2+ ]=0.004M
Cd(s) | Cd²*(aq) || Cu²*(aq) | Cu(s)
Half-Reaction
E° (V)
Cl2 (g) + 2e¯ –→
2CI (aq)
1.36
1.07
Br2 (1) + 2e
→ 2Br (aq)
0.80
Ag (aq) + e¯ –→ Ag(s)
Cu²* (aq) + 2e→ Cu(s)
2H"(aq) + 2e¯ → H2(g)
Pb2+ (aq) + 2e
Cd2+ (aq) + 2e
Al* (aq) + 3e →
Be2* (aq) + 2e
0.34
0.00
-0.13
Pb(s)
-0.40
→ Cd(s)
-1.66
Al(s)
-1.85
→ Be(s)
Transcribed Image Text:Cd(s) | Cd²*(aq) || Cu²*(aq) | Cu(s) Half-Reaction E° (V) Cl2 (g) + 2e¯ –→ 2CI (aq) 1.36 1.07 Br2 (1) + 2e → 2Br (aq) 0.80 Ag (aq) + e¯ –→ Ag(s) Cu²* (aq) + 2e→ Cu(s) 2H"(aq) + 2e¯ → H2(g) Pb2+ (aq) + 2e Cd2+ (aq) + 2e Al* (aq) + 3e → Be2* (aq) + 2e 0.34 0.00 -0.13 Pb(s) -0.40 → Cd(s) -1.66 Al(s) -1.85 → Be(s)
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