Lithium metal is a very strong reducing agent and reacts vigorously with 1 M hydrochloric acid to produce hydrogen gas. The relevant half reactions are Li+(ag) + e- = Li(s) E = -3.04 V 2H+(ag) + 2e- = H2g) E = +0.00 V - Lithium also reacts vigorously with pH-neutral iced water. Assuming a hydrogen gas pressure of 0.1 atm and a lithium ion concentration of 0.1 mol/L and assuming that the standard cell potential does not change with temperature, determine the cell potential. - A more accurate calculation for the previous part would need to take into account the change in E° with temperature. What information would be needed to do this, and do you expect the actual cell potential would be higher or lower than that calculated? [Hint: Gibbs Free Energy change.]
Lithium metal is a very strong reducing agent and reacts vigorously with 1 M hydrochloric acid to produce hydrogen gas. The relevant half reactions are Li+(ag) + e- = Li(s) E = -3.04 V 2H+(ag) + 2e- = H2g) E = +0.00 V - Lithium also reacts vigorously with pH-neutral iced water. Assuming a hydrogen gas pressure of 0.1 atm and a lithium ion concentration of 0.1 mol/L and assuming that the standard cell potential does not change with temperature, determine the cell potential. - A more accurate calculation for the previous part would need to take into account the change in E° with temperature. What information would be needed to do this, and do you expect the actual cell potential would be higher or lower than that calculated? [Hint: Gibbs Free Energy change.]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Lithium metal is a very strong reducing agent and reacts vigorously with 1 M hydrochloric acid to produce hydrogen gas. The relevant half reactions are Li+(ag) + e- = Li(s) E = -3.04 V
2H+(ag) + 2e- = H2g) E = +0.00 V
- Lithium also reacts vigorously with pH-neutral iced water. Assuming a hydrogen gas pressure of 0.1 atm and a lithium ion concentration of 0.1 mol/L and assuming that the standard cell potential does not change with temperature, determine the cell potential.
- A more accurate calculation for the previous part would need to take into account the change in E° with temperature. What information would be needed to do this, and do you expect the actual cell potential would be higher or lower than that calculated? [Hint: Gibbs Free Energy change.]
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