The equilibrium constant, K, for a redox reaction is related to the standard potential, E, by the equation In K = nFE RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol K), and T is the Kelvin temperature. Standard reduction potentials ▶ Part A Part B Calculate the standard cell potential (E°) for the reaction Eo == Submit D μA Reduction half-reaction Ag+ (aq) + e→Ag(s) Cu²+ (aq) + 2e →Cu(s) Sn+ (aq) + 4e →Sn(s) -0.125 Previous Answers 2H+ (aq) + 2e →H₂(g) Ni2+ (aq) + 2e →Ni(s) Fe2+ (aq) + 2e →Fe(s) Zn²+ (aq) + 2e →Zn(s) Al³+ (aq) + 3e →Al(s) -1.66 Mg2+ (aq) + 2e →Mg(s) -2.37 V E° (V) 0.80 if K = 2.80x10-4. Express your answer to three significant figures and include the appropriate units. ► View Available Hint(s) 0.34 ? 0.15 X Incorrect; Try Again; 4 attempts remaining 0 -0.26 -0.45 -0.76 X(s) +Y+ (aq) →X+ (aq) + Y(s) Review | Constants I Periodic Table

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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.144QP
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The equilibrium constant, K, for a redox reaction is
related to the standard potential, E, by the
equation
In K =
nFE
where n is the number of moles of electrons
transferred, F (the Faraday constant) is equal to
96,500 C/(mol e), R (the gas constant) is
equal to 8.314 J/(mol K), and T is the Kelvin
temperature.
Standard reduction potentials
▶
Part A
Part B
Calculate the standard cell potential (E°) for the reaction
Eo ==
Submit
D
μA
Reduction half-reaction
Ag+ (aq) + e→Ag(s)
Cu²+ (aq) + 2e →Cu(s)
Sn+ (aq) + 4e¯→Sn(s)
2H+ (aq) + 2e →H₂(g)
Ni2+ (aq) + 2e →Ni(s)
Fe2+ (aq) + 2e →Fe(s)
0.125
Previous Answers
V
E° (V)
0.80
if K = 2.80x10-4.
Express your answer to three significant figures and include the appropriate units.
► View Available Hint(s)
0.34
?
0.15
Zn²+ (aq) +2e →Zn(s)
-0.76
Al³+ (aq) + 3e →Al(s) -1.66
Mg2+ (aq) + 2e →Mg(s) -2.37
X Incorrect; Try Again; 4 attempts remaining
0
-0.26
-0.45
X(s) + Y+ (aq) →X+ (aq) + Y(s)
Review | Constants I Periodic Table
Transcribed Image Text:The equilibrium constant, K, for a redox reaction is related to the standard potential, E, by the equation In K = nFE where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol K), and T is the Kelvin temperature. Standard reduction potentials ▶ Part A Part B Calculate the standard cell potential (E°) for the reaction Eo == Submit D μA Reduction half-reaction Ag+ (aq) + e→Ag(s) Cu²+ (aq) + 2e →Cu(s) Sn+ (aq) + 4e¯→Sn(s) 2H+ (aq) + 2e →H₂(g) Ni2+ (aq) + 2e →Ni(s) Fe2+ (aq) + 2e →Fe(s) 0.125 Previous Answers V E° (V) 0.80 if K = 2.80x10-4. Express your answer to three significant figures and include the appropriate units. ► View Available Hint(s) 0.34 ? 0.15 Zn²+ (aq) +2e →Zn(s) -0.76 Al³+ (aq) + 3e →Al(s) -1.66 Mg2+ (aq) + 2e →Mg(s) -2.37 X Incorrect; Try Again; 4 attempts remaining 0 -0.26 -0.45 X(s) + Y+ (aq) →X+ (aq) + Y(s) Review | Constants I Periodic Table
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