2+ The free energy change for the following reaction at 25 °C, when Cu²+ = 1.12 M and [ca²+] = 0.00427 M, is -157 kJ: Cu²+ (1.12 M) + Cd(s) → Cu(s) + Cd²+ (0.00427 M) What is the cell potential for the reaction as written under these conditions? Ecell V AG-157 kJ Would this reaction be spontaneous in the forward or the reverse direction? O forward direction reverse direction
2+ The free energy change for the following reaction at 25 °C, when Cu²+ = 1.12 M and [ca²+] = 0.00427 M, is -157 kJ: Cu²+ (1.12 M) + Cd(s) → Cu(s) + Cd²+ (0.00427 M) What is the cell potential for the reaction as written under these conditions? Ecell V AG-157 kJ Would this reaction be spontaneous in the forward or the reverse direction? O forward direction reverse direction
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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The free energy change for the following reaction at 25 °C, when Cu²+ - 1.12 M and
[ca²+] = 0.00427 M, is -157 kJ:
Cu²+ (1.12 M) + Cd(s) → Cu(s) + Cd²+ (0.00427 M)
What is the cell potential for the reaction as written under these conditions?
Ecell
V
AG-157 kJ
Would this reaction be spontaneous in the forward or the reverse direction?
O forward direction
reverse direction](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F44bcc854-a672-4b6c-b0fb-367be49d6297%2F22b53435-9716-4b62-b8a1-d26c2b2e6705%2Fpbko7ca_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2+
The free energy change for the following reaction at 25 °C, when Cu²+ - 1.12 M and
[ca²+] = 0.00427 M, is -157 kJ:
Cu²+ (1.12 M) + Cd(s) → Cu(s) + Cd²+ (0.00427 M)
What is the cell potential for the reaction as written under these conditions?
Ecell
V
AG-157 kJ
Would this reaction be spontaneous in the forward or the reverse direction?
O forward direction
reverse direction
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