The free energy change for the following reaction at 25 °C, when [Sn2+] = 1.19 M and [Zn2+] = 7.83×10-3 M, is -133 kJ: Sn2+(1.19 M) + Zn(s)→ Sn(s) + Zn2+(7.83x10-3 M) AG = -133 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
The free energy change for the following reaction at 25 °C, when [Sn2+] = 1.19 M and [Zn2+] = 7.83×10-3 M, is -133 kJ: Sn2+(1.19 M) + Zn(s)→ Sn(s) + Zn2+(7.83x10-3 M) AG = -133 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
Chemistry
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Question
![The free energy change for the following reaction at 25 °C,
when [Sn2+] = 1.19 M and [Zn2+] = 7.83×10-3 M, is
-133 kJ:
Sn2+(1.19 M) + Zn(s)→ Sn(s) + Zn2+(7.83×10-3 M)
AG
= -133 kJ
What is the cell potential for the reaction as written under
these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the
reverse direction?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7618b616-74f8-4a0e-8ac2-3556d0780420%2Fcf4244c2-aa60-4ef4-b35f-3c4f4c5d84be%2F8hap433_processed.png&w=3840&q=75)
Transcribed Image Text:The free energy change for the following reaction at 25 °C,
when [Sn2+] = 1.19 M and [Zn2+] = 7.83×10-3 M, is
-133 kJ:
Sn2+(1.19 M) + Zn(s)→ Sn(s) + Zn2+(7.83×10-3 M)
AG
= -133 kJ
What is the cell potential for the reaction as written under
these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the
reverse direction?
![The free energy change for the following reaction at 25 °C,
when [Hg2+] = 1.14 M and [Sn2+] = 1.44×10-3 M, is
%3D
-209 kJ:
Hg2+(1.14 M) + Sn(s)→ Hg(1) + Sn²+(1.44x10-3 M)
AG = -209 kJ
What is the cell potential for the reaction as written under
these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the
reverse direction?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7618b616-74f8-4a0e-8ac2-3556d0780420%2Fcf4244c2-aa60-4ef4-b35f-3c4f4c5d84be%2Fnsd34ho_processed.png&w=3840&q=75)
Transcribed Image Text:The free energy change for the following reaction at 25 °C,
when [Hg2+] = 1.14 M and [Sn2+] = 1.44×10-3 M, is
%3D
-209 kJ:
Hg2+(1.14 M) + Sn(s)→ Hg(1) + Sn²+(1.44x10-3 M)
AG = -209 kJ
What is the cell potential for the reaction as written under
these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the
reverse direction?
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