The free energy change for the following reaction at 25 °C, when [Hg2+] = 1.11 M and [H+] = 8.68x10-3 M, is -177 kJ: %3D Hg2+(1.11 M) + H2(g) Hg(1) + 2H+(8.68×10-3 M) AG = -177 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? forward reverse Submit Answer Retry Entire Group 6 more group attempts remaining

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter18: Electrochemistry
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Problem 18.43QE: For each of the reactions, calculate E from the table of standard potentials, and state whether the...
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The free energy change for the following reaction at 25 °C, when [Hg2+] = 1.11 M and [H+] =
%3D
8.68x10-3 M, is -177 kJ:
Hg2+(1.11 M) + H2(g) Hg(1) + 2H+(8.68×10-3
M)
AG = -177 kJ
%3D
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?
forward
reverse
Submit Answer
Retry Entire Group
6 more group attempts remaining
V.
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Hg2+] = 1.11 M and [H+] = %3D 8.68x10-3 M, is -177 kJ: Hg2+(1.11 M) + H2(g) Hg(1) + 2H+(8.68×10-3 M) AG = -177 kJ %3D What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? forward reverse Submit Answer Retry Entire Group 6 more group attempts remaining V.
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