Calculate the standard cell potential at 25°C for the following cell reaction from standard free energies of formation:2Al(s) + 3H3²+ (aq) → 2A1š+ (ag) + 3Hg(1)Standard Free Energy of FormationIonAG; (kJ/mol)Als+ (aq)-485.0Zn2+ (aq)-147.0Co2+ (ag)-54.4Ni²+ (ag)-45.6Pb?+ (ag)-24.39Cu²+ (ag)65.52Hg²+ (aq)164.4Fe?+ (ag)-78.87Standard cell potentialV Calculate the standard cell potential of the cell corresponding to the oxidation of oxalic acid,H2 C204, by chlorate ion,ClO3 (ag).3H2C204(aq) + ClO3 (ag) → 6CO2 (g) + Cl¯ (ag) + 3H2O(1)AG; forH2 C204 (aq) is -698 kJ.Youmayneed to use the following data.Substance or ion AG; (kJ/mol)ClO3 (ag)-292.3CO2 (g)-394.4Cl" (aq)-131.3H2O(1)-237.1Standard cell potential =V

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Calculate the standard cell potential at 25°C for the following cell reaction from standard free energies of formation: 2A1(s) + 3H&²+ (ag) → 2Al** (aq) + 3Hg(!)

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

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Chapter1: Chemical Foundations

Section: Chapter Questions

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

Calculate the standard cell potential at 25°C for the following cell reaction from standard free energies of formation:
2Al(s) + 3H3²+ (aq) → 2A1š+ (ag) + 3Hg(1)
Standard Free Energy of Formation
Ion
AG; (kJ/mol)
Als+ (aq)
-485.0
Zn2+ (aq)
-147.0
Co2+ (ag)
-54.4
Ni²+ (ag)
-45.6
Pb?+ (ag)
-24.39
Cu²+ (ag)
65.52
Hg²+ (aq)
164.4
Fe?+ (ag)
-78.87
Standard cell potential
V

Calculate the standard cell potential of the cell corresponding to the oxidation of oxalic acid,
H2 C204, by chlorate ion,
ClO3 (ag).
3H2C204(aq) + ClO3 (ag) → 6CO2 (g) + Cl¯ (ag) + 3H2O(1)
AG; for
H2 C204 (aq) is -698 kJ.
You
may
need to use the following data.
Substance or ion AG; (kJ/mol)
ClO3 (ag)
-292.3
CO2 (g)
-394.4
Cl" (aq)
-131.3
H2O(1)
-237.1
Standard cell potential =
V

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