The free energy change for the following reaction at 25 °C, when [Cd²+]= 9.77×10-3 M and [Cu2+] = 1.12 M, is 119 kJ: Cd2+(9.77x10-3 M) + 2Cu*(aq)Cd(s) + 2Cu2*(1.12 M) AG = 119 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction?

The free energy change for the following reaction at 25 °C, when [Cd²+]= 9.77×10-3 M and [Cu2+] = 1.12 M, is 119 kJ: Cd2+(9.77x10-3 M) + 2Cu(aq)Cd(s) + 2Cu2(1.12 M) AG = 119 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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K124.
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