1. Two masses m₁ and m2 are placed on either end of an ideal spring as shown in the diagram below: The masses are pushed together compressing the spring with a spring constant k, a distance x, and then released. m2 has twice the mass of m, and the surface can be considered frictionless. a) How much faster will m₁ be traveling to the left after the spring fully decompresses then m₂ will be traveling to the right? (show momentum barcharts) b) Which mass will have a greater kinetic energy after the spring is finished decompressing? Explain. c) Write an equation for v, the speed of m2 after the spring fully decompresses, in terms of k, x, and m₁. (show energy bar charts)

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1. Two masses m₁ and m2 are placed on either end of an ideal spring as shown in the
diagram below:
The masses are pushed together compressing the spring with a spring constant k, a
distance x, and then released. m2 has twice the mass of m, and the surface can be
considered frictionless.
a) How much faster will m₁ be traveling to the left after the spring fully
decompresses then m₂ will be traveling to the right? (show momentum barcharts)
b) Which mass will have a greater kinetic energy after the spring is finished
decompressing? Explain.
c) Write an equation for v, the speed of m2 after the spring fully decompresses, in
terms of k, x, and m₁. (show energy bar charts)
Transcribed Image Text:1. Two masses m₁ and m2 are placed on either end of an ideal spring as shown in the diagram below: The masses are pushed together compressing the spring with a spring constant k, a distance x, and then released. m2 has twice the mass of m, and the surface can be considered frictionless. a) How much faster will m₁ be traveling to the left after the spring fully decompresses then m₂ will be traveling to the right? (show momentum barcharts) b) Which mass will have a greater kinetic energy after the spring is finished decompressing? Explain. c) Write an equation for v, the speed of m2 after the spring fully decompresses, in terms of k, x, and m₁. (show energy bar charts)
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