Mr. A leaves his home for his office. He drives 24 km away in a direction 52° north of east. Then, he takes turns and drives 36 km in a direction 124° west of north. Find the distance and direction from the shopper's home to the restaurant. a) Total distance he drove = 60 Unit km b) x and y-components of the displacement vector: x- component = 52 × y-component=36 × b) Magnitude of the displacement of his office from his home = Unit (m c) The direction of his office from his home = degree.
Mr. A leaves his home for his office. He drives 24 km away in a direction 52° north of east. Then, he takes turns and drives 36 km in a direction 124° west of north. Find the distance and direction from the shopper's home to the restaurant. a) Total distance he drove = 60 Unit km b) x and y-components of the displacement vector: x- component = 52 × y-component=36 × b) Magnitude of the displacement of his office from his home = Unit (m c) The direction of his office from his home = degree.
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![Mr. A leaves his home for his office. He drives 24 km
away in a direction 52° north of east. Then, he takes
turns and drives 36 km in a direction 124° west of
north. Find the distance and direction from the
shopper's home to the restaurant.
a) Total distance he drove = 60
Unit
km
b) x and y-components of the displacement vector: x-
component = 52
×
y-component=36
×
b) Magnitude of the displacement of his office from his
home =
Unit (m
c) The direction of his office from his home =
degree.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0683ea1f-b080-4dff-907a-5e7c40bcdf74%2F6bd1d8c9-7d67-45bc-851c-cc549d205e6e%2Fho8y82h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Mr. A leaves his home for his office. He drives 24 km
away in a direction 52° north of east. Then, he takes
turns and drives 36 km in a direction 124° west of
north. Find the distance and direction from the
shopper's home to the restaurant.
a) Total distance he drove = 60
Unit
km
b) x and y-components of the displacement vector: x-
component = 52
×
y-component=36
×
b) Magnitude of the displacement of his office from his
home =
Unit (m
c) The direction of his office from his home =
degree.
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