60° Y F 20kN = 09 201 y 50 kN √√2 3 40 kN

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If theta = 60° and F = 20 kN, determine the magnitude of the resultant force and its direction measured clockwise from the positive x axis.

60°
Y
F
20kN =
09
201
y
50 kN
√√2
3
40 kN
Transcribed Image Text:60° Y F 20kN = 09 201 y 50 kN √√2 3 40 kN
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