Given that the lowering operator's action is S. | s, m> = ch|s, m-1>, show that 1/2 - m (m-1)] 2. c. [s (s+1)-1 Hint: Proceed similarly to what we did in class to show that c. in the expression S.|s, m>= c. | s, m+1 > satisfies c. = [s (s+1) - m (m+1)] 1/2
Given that the lowering operator's action is S. | s, m> = ch|s, m-1>, show that 1/2 - m (m-1)] 2. c. [s (s+1)-1 Hint: Proceed similarly to what we did in class to show that c. in the expression S.|s, m>= c. | s, m+1 > satisfies c. = [s (s+1) - m (m+1)] 1/2
Question
![Given that the lowering operator's action is S. | s, m> = ch|s, m-1>, show that
1/2
- m (m-1)] 2.
c. [s (s+1)-1
Hint: Proceed similarly to what we did in class to show that c. in the expression
S.|s, m>= c. | s, m+1 > satisfies c. = [s (s+1) - m (m+1)] 1/2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd9d42bd-58d8-46f6-aafa-68a44e3938d9%2F139300e0-44bb-427d-a314-47584804a118%2F52744m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given that the lowering operator's action is S. | s, m> = ch|s, m-1>, show that
1/2
- m (m-1)] 2.
c. [s (s+1)-1
Hint: Proceed similarly to what we did in class to show that c. in the expression
S.|s, m>= c. | s, m+1 > satisfies c. = [s (s+1) - m (m+1)] 1/2
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