Extra Credit Computation In the figure, a T-bar ski tow pulls a skier up a hill inclined at 10° above horizontal. The skier starts from rest and is pulled by a cable that exerts a tension of 300 N at an angle of 30° above the surface of the hill. The mass of the skier is 60 kg and the effective coefficient of kinetic friction between the skis and the snow is 0.100. (a) Draw a force diagram for the skier. (3 pts) FT 3000 30° 10° Ffx 60 Fg L 0-40° F9 11 F911 = (b) What is the skier's acceleration up the hill? (5 pts) M Sin 40 Fgma cos 46 = = 377.96N 450.4 N
Extra Credit Computation In the figure, a T-bar ski tow pulls a skier up a hill inclined at 10° above horizontal. The skier starts from rest and is pulled by a cable that exerts a tension of 300 N at an angle of 30° above the surface of the hill. The mass of the skier is 60 kg and the effective coefficient of kinetic friction between the skis and the snow is 0.100. (a) Draw a force diagram for the skier. (3 pts) FT 3000 30° 10° Ffx 60 Fg L 0-40° F9 11 F911 = (b) What is the skier's acceleration up the hill? (5 pts) M Sin 40 Fgma cos 46 = = 377.96N 450.4 N
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Transcribed Image Text:Extra Credit
Computation
In the figure, a T-bar ski tow pulls a skier up a hill inclined at 10°
above horizontal. The skier starts from rest and is pulled by a cable that
exerts a tension of 300 N at an angle of 30° above the surface of the
hill. The mass of the skier is 60 kg and the effective coefficient of
kinetic friction between the skis and the snow is 0.100.
(a) Draw a force diagram for the skier. (3 pts)
FT
3000
30°
10°
Ffx
60
Fg L
0-40°
F9 11
F911
=
(b) What is the skier's acceleration up the hill? (5 pts)
M Sin 40
Fgma cos 46 =
= 377.96N
450.4 N
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