1. Read the section above about balancing charges and give formulas that represent overall neutral compounds between the following pairs of ions. + a. Cs and Cl- + b. Cs and Se²- c. Fe2+ and Br d. Fe3+ and Br e. Fe2+ and CO3²- 2-
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- The following Lewis representation depicts a reaction between one atom of a group nonmetal. •X. + •Ÿ: Use the References to access important values if needed for this question. In this representation, each x²+ + atom loses The bonds that form in the product would be 2- [BY:] ² electron(s) and each metal and one atom of a group atom gains electron(s).eaching and lear X G The element in period 5 that has X ment/takeCovalentActivity.do?locator=assignment-take [Review Topics] [References] We can draw three inequivalent Lewis structures for the sulfite ion, SO32. The concepts of formal charge and electronegativity can help us choose the structure that is the best representation. Formal Charge 1. Assign formal charges to the elements in each of the structures below. Note: Count oxygen atoms starting from the left for each structure. 40 S 01 02 03 Submit Answer :O: 4- --0000 :0: 4+ C Solved The following Lewis diagr x 2. The best Lewis structure for SO3²- is V. fg Yo 144 :0: Retry Entire Group 9 more group attempts remaining fo B 0% " A a 112 :0: C :0: + O ins prt sc Previous A ENG delete home 11:54 A 11/28/20 endPlease do it correctly.
- Now, using the table of bond energies, calculate the enthalpy change for... CH3Br + OH --> CH3OH + Br AH = Σ(Bond energies of the bonds broken) - Σ(Bond energies of the bonds formed What is the AH for this reaction? Write out your work. Average Single Bond Energies (kJ per mole) HCN OF Si P S CI Br I H 436 414 389 464 569 293 318 339 431 368 297 347 293 351 439 289 264 259 330 276 238 159 201 272 201 243 209 138 184 368 351 205 159 540 490 285 255 197 176 213 226 360 289 LADS&SHONCH с Si CI Br 201 C N 0 0 213 230 331 272 213 213 251 213 243 218 209 192 180 151 Average Multiple Bond Energies (kJ per mole) N= N 418 N=N 946 C=C 611 C=C 837 C=0 803 N=0 590 891 498 C=0 745 C=O 1075 In CO₂ Only1. Chapter 8, Problem 66: Use bond energy values (Table 8.4) to estimate AH for each of the following reactions. H- a. HCN(g) + 2H2(g) → H н (g) b. H. (g) + 2F2(g) → N2(g) + 4HF(g)Write Lewis structures that obey the octet rule for each of the following. a. HCN b. PH3 c. CHCl3 d. NH4+ e. H2CO f. SeF2 g. CO2 h. O2 i. HBr Except for HCN and H2CO, the first atom listed is the central atom. For HCN and H2CO , carbon is the central atom.
- 9. Use the following data to calculate the lattice energy of Cao. The enthalpy of formation of Cao is –636 kj/mol. The enthalpy of sublimation of Ca is +192 kj/mol, the first ionization energy of Ca is +590 kj/mol, and the second ionization energy of Ca is +1145 kj/mol. The enthalpy of dissociation of 02 is +494 kj/mol of 02 molecules, the first electron affinity of O is -141 kj/mol of 0 atoms, and the second electron affinity of 0 is +845 kj/mol of 0¯ ions.Ff.248.14.
- number 2 asks A B or CInert xenon actually forms many compounds, especially with highly electronegative fluorine. 0 The AH values for xenon difluoride, tetrafluoride, and hexafluoride are -105, -284, and f -402 kJ/mol, respectively. Find the average bond energy of the Xe- -F bonds in each fluoride. Xenon difluoride kJ/mol Xenon tetrafluoride kJ/mol Xenon hexafluoride kJ/mol2. Calculate the lattice energy of MgO, given the following: Mg(s) + ¼O:(g) → Mg0(s) AH = -602 kJ AH = 150 kJ AH = 737 kJ Mg(s) → Mg(g) O(g) + 2e (g) → 0*(g) 20(g)→0:(g) Mg(g) → Mg*(g) + 2 e (g) AH = -494 kJ AH = 2180 kJ