3. For the sampling, since we-hadina mar Frequency of 24H2, than the sample need to be at (10-20) times. There fore the sampling an appropriate rate is at 200KHz • YOOK H at (1) 5. Analog signal √(E) Vin = 6 sinwt &max = 24H₂ -6 6 tCms a resoultion to be less than •We 2mv 0.002 > Vrange 2n "I could have Selected a range ±6V So instead, I select a range of ± 12V (Saftey factor) (2) 0.002) 24V 2n 2n 24 0.002 I need the bit size n) 13.55 of 14 bit in A/D converter 27 12000 log (12,0001 n ·log (2) log (12000) →³n > Tog (2)
3. For the sampling, since we-hadina mar Frequency of 24H2, than the sample need to be at (10-20) times. There fore the sampling an appropriate rate is at 200KHz • YOOK H at (1) 5. Analog signal √(E) Vin = 6 sinwt &max = 24H₂ -6 6 tCms a resoultion to be less than •We 2mv 0.002 > Vrange 2n "I could have Selected a range ±6V So instead, I select a range of ± 12V (Saftey factor) (2) 0.002) 24V 2n 2n 24 0.002 I need the bit size n) 13.55 of 14 bit in A/D converter 27 12000 log (12,0001 n ·log (2) log (12000) →³n > Tog (2)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Design an Analog to Digital converter system to sample a voltage = 6 sin wt. This signal
has a maximum frequency of 2000 Hz. You want to have a quantization error of
less than 2 millivolts. Specify: (1) the range you would use, (2) the bit size, and (3) the sampling rate. Explain and show your calculations. (Note: quantization error = ½ of the resolution;
resolution = voltage value associated with a change of the least significant bit).
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